Solving Inequalities Algebra

.5(x - 8) < 2 

• x > 20

• x < 20

• x > 12

• x < 12

Tags

CCSS.7.EE.B.4B

3(x - 3) ≤ 2(x + 2)

• x ≤ -5

• x ≥ 5

• x ≥ 13

• x ≤ 13

Translate: 5 times a number is at least 60.

• 5x < 60

• 5x > 60

• 5x ≤ 60

• 5x ≥ 60

Tags

CCSS.6.EE.B.8

A number increased by 4 is no more than -18.

• x + 4 < -18

• x + 4 > -18

• x + 4 ≤ -18

• x + 4 ≥ -18

Tags

CCSS.7.EE.B.4B

Translate:

Twice a number is smaller than 42.

• 2x < 42

• 2x > 42

• 2x ≤ 42

• 2x ≥ 42

Tags

CCSS.6.EE.B.8

Solve:
3 | 2x + 7| - 7 < -4

• x < -3 and x > -5/3

• x < -3 and x > -4

• all real numbers

• no solution

Solve.
-5|x - 4| > -20

• x < 8 and x > 0

• x > 8 or x < 0

• all real numbers

• no solution

Solve for r.

• r ≥ -38 and r ≤ 32

• r > -38 and r < 32

• r ≥ -38 or r ≤ 32

• r > -38 or r < 32

| x - 2 | > 3
Is this an "and"  or an "or" problem?

• and

• or

What is the first step?

• Get the absolute value alone by dividing both sides by 5

• Drop the absolute value bars and add 7 and 5 together

• Get the absolute value alone by subtracting 5 from both sides