
System of Equations with Dimes, Nickels, Quarters
Authored by Anthony Clark
Mathematics
11th Grade
CCSS covered

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8 questions
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1.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
A cashier has 25 coins consisting of nickels, dimes, and quarters with a value of $4.90. If the number of dimes is 1 less than twice the number of nickels, how many of each type of coin does she have?
nickels is 20
dimes is 3
quarters is 2
nickels is 3
dimes is 5
quarters is 17
nickels is 13
dimes is 10
quarters is 2
nickels is 12
dimes is 10
quarters is 3
2.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
A coin collector has 31 dimes and nickels with a total value of $2.40. How many of each coin does he have?
x + y = 31
10x + 5y = 2.40
x - y = 31
.10x + .05y = 2.40
x + y = 31
.10x + .05y = 2.40
x + y = 2.40
.10x + .05y = 31
Tags
CCSS.8.EE.C.8C
3.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
Dennis mowed his next door neighbor’s lawn for a handful of dimes and nickels, 80 coins in all. Upon completing the job he counted out the coins and it came to $6.60. Which system of equations could be used to find the exact number of dimes and nickels?
d + n = 6.60
10d + 5n = 80
d + n = 80
d + n = 6.60
d + n = 80
.10d + .05n = 6.60
d + n = 80
.05d + .10n = 6.60
Tags
CCSS.8.EE.C.8C
4.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
Laura has $.95 in dimes and nickels. She has a total of 11 coins. how many of each type does she have?
d + n = 11
.10d + .05n = 0.95
d + n = 11
10d + 5n = 0.95
d + n = .95
.10d + .05n = 11
d - n = 11
.10d - .05n = 0.95
Tags
CCSS.8.EE.C.8C
5.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
John has 14 coins that have a total of $2.30 The coins are nickels and quarters. How many of each coin does he find?
N + Q = 14
.05N + .25Q = 2.30
N - Q = 14
5N + 25Q = 2.30
N + Q = 2.30
.05N + .25Q = 14
N - Q = 14
.05N + .25Q = 2.30
Tags
CCSS.8.EE.C.8C
6.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
Renee has $3.75 in dimes and quarters. The number of quarters is two less than three times the number of dimes. Write a system to represent the situation.
d + .25q = 3.75
q = 2d - 3
.1d + .25q = 3.75
q = 3d + 2
.1d + .25q = 3.75
q = 3d - 2
.01d + .25q = 3.75
q = 3d + 2
7.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
A collection of thirty-five coins contains nickels and dimes. The total face value of the coins is $2.55. Write a system of equations.
.05n + .1d = 35
.05n + .1d = 2.55
n + d = 2.55
.05n + .1d = 35
n + d = 35
5n + 10d = 2.55
n + d = 35
.05n + .1d = 2.55
Tags
CCSS.HSA.CED.A.3
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