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System of Equations with Dimes, Nickels, Quarters

Authored by Anthony Clark

Mathematics

11th Grade

CCSS covered

System of Equations with Dimes, Nickels, Quarters
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8 questions

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1.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

A cashier has 25 coins consisting of nickels, dimes, and quarters with a value of $4.90. If the number of dimes is 1 less than twice the number of nickels, how many of each type of coin does she have?

nickels is 20

dimes is 3

quarters is 2

nickels is 3

dimes is 5

quarters is 17

nickels is 13

dimes is 10

quarters is 2

nickels is 12

dimes is 10

quarters is 3

2.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

A coin collector has 31 dimes and nickels with a total value of $2.40. How many of each coin does he have?

x + y = 31

10x + 5y = 2.40

x - y = 31

.10x + .05y = 2.40

x + y = 31

.10x + .05y = 2.40

x + y = 2.40

.10x + .05y = 31

Tags

CCSS.8.EE.C.8C

3.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Dennis mowed his next door neighbor’s lawn for a handful of dimes and nickels, 80 coins in all. Upon completing the job he counted out the coins and it came to $6.60. Which system of equations could be used to find the exact number of dimes and nickels?

d + n = 6.60

10d + 5n = 80

d + n = 80

d + n = 6.60

d + n = 80

.10d + .05n = 6.60

d + n = 80

.05d + .10n = 6.60

Tags

CCSS.8.EE.C.8C

4.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Laura has $.95 in dimes and nickels. She has a total of 11 coins. how many of each type does she have?

d + n = 11

.10d + .05n = 0.95

d + n = 11

10d + 5n = 0.95

d + n = .95

.10d + .05n = 11

d - n = 11

.10d - .05n = 0.95

Tags

CCSS.8.EE.C.8C

5.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

John has 14 coins that have a total of $2.30 The coins are nickels and quarters. How many of each coin does he find?

N + Q = 14

.05N + .25Q = 2.30

N - Q = 14

5N + 25Q = 2.30

N + Q = 2.30

.05N + .25Q = 14

N - Q = 14

.05N + .25Q = 2.30

Tags

CCSS.8.EE.C.8C

6.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Renee has $3.75 in dimes and quarters. The number of quarters is two less than three times the number of dimes. Write a system to represent the situation.

d + .25q = 3.75

q = 2d - 3

.1d + .25q = 3.75

q = 3d + 2

.1d + .25q = 3.75

q = 3d - 2

.01d + .25q = 3.75

q = 3d + 2

7.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

A collection of thirty-five coins contains nickels and dimes. The total face value of the coins is $2.55. Write a system of equations.

.05n + .1d = 35

.05n + .1d = 2.55

n + d = 2.55

.05n + .1d = 35

n + d = 35

5n + 10d = 2.55

n + d = 35

.05n + .1d = 2.55

Tags

CCSS.HSA.CED.A.3

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