Finding the Particular Solution

Find y, if y'= x^{2 ext{ }} , and given the initial condition y(0)=1

Find the particular solution for y if dy/dx = 2x√y and y = 4 when x = 3.

• 2√y = x² + C

• y = (x² + 25)²/4

• y = (x²/2-5/2)^1/2

• y = x⁴/4

dy/dx = 4x/y. Suppose y(0)=1

The particular solution is

• B

• C

• D

• E

Find the Particular Solution