Solving Algebraic Expressions

2(a+3) use a=4

• 14

• 11

• 7

• 12

5(10-a) use a=6

• 50

• 4

• 20

• 1

When a variable or number has no exponent, it is implied that the exponent is

• 0

• 1

• 2

• -1

(r⁴)⁶

• 10r

• r¹⁰

• 24r

• r²⁴

2(a - 5) + 2
when a = 15

• 22

• 27

• 14

• 7

6a - 3d
when a = 1, d = 2

• 3

• 12

• 1

• 0

Evaluate when a = 15:
2(a - 5) + 2

• 22

• 27

• 14

• 7

Evaluate when x = 8:
2x + x - 10

• 34

• 22

• 14

• 24

6a + 2(c - b)
when a = 2, b = 1, c = 9

• 4

• -4

• 28

• 8

Simplify: 6x + 2m

when x = 14 and m = (-9)

• 66

• -66

• 102

• 13