Ada Composite Area

Quiz
•
Mathematics
•
7th Grade
•
Hard
Anthony Clark
FREE Resource
14 questions
Show all answers
1.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
At a restaurant, a waiter pushed 4 identical square tables together as shown in the diagram. The width of each table is 5 feet. Which of the following methods could the waiter use to determine the total serving area created by the 4 square tables?
Multiply 5 by 5, then multiply the product by 4.
Multiply 5 by 5, then multiply the product by 5.
Add 4 plus 4, then multiply the sum by 5.
Multiply 4 by 5, then add 4 to the product.
2.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
The model of the backboard of a basketball goal shown on your recording sheet is composed of a rectangle and a semicircle. Use a ruler to measure the dimensions of the model to the nearest half inch.
Which measurement is closest to the area of the model of the backboard in square inches?
18.56 in.2
31.12 in.2
12.28 in.2
23.56 in.2
3.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
Which procedure should be used to find the area of the shaded region?
Subtract the perimeter of the trapezoid from the area of both circles.
Subtract the circumference of both circles from the area of the trapezoid.
Subtract the area of the trapezoid from the area of both circles.
Subtract the area of both circles from the area of the trapezoid.
4.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
Ms. Robbins wants to carpet her living room floor as shown in the figure. Carpet costs $22 per square foot and there is an installation fee of $250. How much will it cost Ms. Robbins to carpet her living room?
$6,600
$6,138
$6,850
$6,388
5.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
What is the approximate area of the figure pictured?
3.53 cm2
7.07 cm2
5.30 cm2
21.20 cm2
6.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
What is the approximate area of the logo?
46 cm2
32 cm2
71 cm2
85 cm2
7.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
Which of the following equations could NOT be used to find the area of the figure shown?
A = 10(15) - 3.75(2.5)(5)
A = 15(10) - 2.5(5) - 3.75(5)
A = 15(10) - [2.5(5) + 3.75(5)]
A = 2(10)(5) + 5(3.75)
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