Finding Zeros of a Polynomial Function

Factor:
 x³-12x²+47x-60=0 when 5 is a root.

• (x-3)(x-4)(x-5)=0

• (x+1)(x-4)(x-5)=0

• (x-3)(x-4)(2x-5)=0

• (x-5)(x-4)(x-5)=0

f(x) = x³ - 9x² - 45x - 27 Find the remaining zeros given that -3 is a zero of f(x).

• {-3, -6 ± 3√5}

• {-3, 6 ± 3√5}

• (-3, 3, 9}

• {-3, 0, 3}

Find all the roots of y=x³-2x²+4x-8  (Hint: Factor)

• -2, 2i, -2i

• 2, 2i, -2i

• 2,-2, 2i

• 1, 2i, 4

Find the factored form of the function graphed:

• y = -(x + 1)(x - 1)(x - 2)

• y= (x + 1)²(2 - x)

• y = (-x + 1)²(x - 2)

• y = -(x - 1)²(x + 2)

This polynomial would have how many roots?

f(x) = 4x⁵ - 3x⁴ + 2x² - 7x + 1

• 7

• 5

• 4

• 1

If the binomial (x - 7) is a factor of the polynomial function f(x), which statement must be true?

• f(7) = -7

• f(7) = 0

• f(-7) = 0

• f(-7) = -7

• (x+6)

• (x-6)

• (x+2)

• (x-2)