Solving Polynomials Step

3y+6+4y-7=-8

• y=-1

• y=-8

• y=1

• y=7

Tags

CCSS.8.EE.C.7B

What is the first step in solving 
(x + 2)(x - 3) = 0      ?

• Plug in zero for x

• Solve for x

• FOIL

• Set each binomial factor equal to zero

Tags

CCSS.HSA-REI.B.4B

x² + 12x + 32 = 0

• x = -4, 8

• x = 4, 8

• x = -4, -8

• x = 0, 12

Tags

CCSS.HSA-REI.B.4B

Solve x² + x – 72 = 0.

• x = -8

• x = -8 or x = 9

• x = 8 or x = -9

• x = 9

Tags

CCSS.HSA-REI.B.4B

Solve m² + 12m - 64 =0.

• 16 and -4

• 9/2 and -3

• 4 and -16

Tags

CCSS.HSA-REI.B.4B

Solve by factoring.
k² + 8k + 12 = 0

• -2, 2

• -2, 4

• -2, -6

• 2, 3

Tags

CCSS.HSA-REI.B.4B

Solve the equation by factoring: n²+11n +30 = 0

• x = -6, -5

• x = 6, 5

• x = 2, 15

• x = -2, -15

Tags

CCSS.HSA-REI.B.4B

r² - 6r + 5 = 0

• r = 5 and 1

• r = 5 and -1

• r = -5 and 1

• r = -5 and -1

Tags

CCSS.HSA-REI.B.4B

Solve the trinomial:

2x²+2x-4=0

• -1,2

• -1,-2

• 1,2

• 1,-2

Tags

CCSS.HSA-REI.B.4B

Solve the trinomial:

12x²-12x - 24 = 0

• -1,2

• 1,2

• 1,-2

• -1,-2

Tags

CCSS.HSA-REI.B.4B