Factor Theorem and Algebraic Identities

• (3 x +25) (3 x- 1)

• (3 x + 5)(3 x - 5)

• (9 x- 1)(3 x - 5)

Find the zeros of the polynomial f(x) = x^3 - 6x^2 + 11x - 6 using the factor theorem.

• x = 2, x = 3, x = 4

• x = 1, x = 2, x = 3

• x = 0, x = -1, x = -2

• x = 4, x = 5, x = 6

Factor x^3 - 2x^2 + x

• x(x - 1)(x + 1)

• x(x - 1)^2

• (x^2 - 1)(x + 1)

• (x^2 - 1)(x - 1)

If (x + 3) is a factor of p(x), then p(- 3) = ​ (a)   .

• 0

• 3

• -3

• None of these.

Given the expressions in the image, what are they equivalent to

(x+8)(x-12) is equivalent to ​ (a)  

(x+9)² - 1 is equivalent to ​ (b)  

-x² +12x -35 is equivalent to ​ (c)  

• B and C

• D and E

• only A

Factor f(x)= x³ - 2x²-13x - 10  given that
(x - 5) is one factor.

• (x- 5)(x - 1)(x - 2)

• (x - 5)(x + 2)(x - 2)

• (x - 5)(x + 2) (x + 1)

• (x - 5)(2x - 13)

If a polynomial has 2 factors, it will have 2 zeros (or 1 zero with a multiplicity of 2).

• True

• False