Linear or Exponential Word Problems

Linear or Exponential Word Problems

9th Grade

19 Qs

quiz-placeholder

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Linear or Exponential Word Problems

Linear or Exponential Word Problems

Assessment

Quiz

Mathematics

9th Grade

Practice Problem

Hard

CCSS
HSF.LE.A.2, HSF.BF.A.2, HSF-IF.C.8B

+3

Standards-aligned

Created by

Anthony Clark

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19 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

You have inherited land that was purchased for $30,000 in 1960. The value of the land increased by approximately 5% per year. What is the approximate value of the land in the year 2011?

$361,223.09

$15,000.00

$31,500.29

$280,500.86

2.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Which of the following functions shows an initial amount of $15 and an increase of 35% each year?

y = 15(35)x

y = 15(0.35)x

y = 15(1.35)x

y = 35(1.15)x

Tags

CCSS.HSF.LE.A.2

3.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Media Image

Is this exponential growth or decay?

Growth because a=1

Growth because there is no a

Decay because b=0.5

Neither because a=0

Tags

CCSS.HSF-IF.C.8B

4.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Media Image

Is this exponential growth or decay?

Growth, because of 7

Growth because of 1.2

Decay, because of 1.2

Decay because of 7

Tags

CCSS.HSF-IF.C.8B

5.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

The value of a car is $15,000 and depreciates at a rate of 8% per year. What is the exponential equation?

y=8(15,000)x

y=15,000(0.92)x

y=15,000(1.08)x

y=15,000(0.08)x

Tags

CCSS.HSF.LE.A.2

6.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Suppose a culture of bacteria begins with 5000 cells and dies by 30% each year. Write an equation that represents this situation.

y=5000(0.7)x

y=5000(1.3)x

y=30(5000)x

y=5000xx

Tags

CCSS.HSF.LE.A.2

7.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

The population of Boringtown decreased annually by 1.8% between the year 2015-2018. In 2015, there were approximately 200,000 people living in Boringtown. Which function models the city's population since 2015?

f(x) = 200,000(1 + 0.018)3

f(x) = 200,000(1 - 0.18)3

f(x) = 200,000(1 + 0.18)3

f(x) = 200,000(1 - 0.018)3

Tags

CCSS.HSF.BF.A.2

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