
Area and Perimeter Word Problems
Authored by Anthony Clark
Mathematics
8th Grade
CCSS covered
Used 1+ times

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15 questions
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1.
FILL IN THE BLANK QUESTION
1 min • 1 pt
A triangular wall needs to be painted. The triangle is an equilateral triangle with 35 metre sides and the height of the wall is 30 metres. Nina wants to make a gold border around the wall. What is the length of the gold border that is needed?
Answer explanation
An equilateral triangle means that all 3 sides are equal. This means you need to add up all 3 sides to get the length of the gold border.
Tags
CCSS.3.MD.D.8
2.
OPEN ENDED QUESTION
1 min • 2 pts
The garden has two sections: a triangle section for vegetables and a circular section for flowers, with the rest grass. The vegetables section is a right-angle with sides of 3.45m and 2.1m. The flower section is 5.7m from one side to the other. What is the total area of each section of the garden? If grass seed costs $1.77/m², how much will it cost to buy enough seed for the grass area?
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Answer explanation
Vegetable Section (Triangle)
Area of triangle = (base × height) ÷ 2
Area = (3.45 × 2.1) ÷ 2 = 3.6225 m²
Flower Section (Circle)
Area of circle = π × r²
Where r is the radius (half the diameter) - Radius = 5.7 ÷ 2 = 2.85m
Area = π × 2.85² ≈ 25.5173 m²
Grass Section
subtract vegetable and flower areas from the total garden area.
TOTAL GARDEN AREA: 52.46m² (8.6 x 6.1)
VEGETABLE & FLOWER GARDENS:
3.6225 m² + 25.5173 m² = 29.1398m²
GRASS AREA = 52.46 - 29.1398 = 23.32m²
Grass Seed Cost = Grass area × Price per m²
= 23.32m² × $1.77/m² = 41.2764
= $41.30
3.
OPEN ENDED QUESTION
1 min • 1 pt
For a school event, circular pizzas with a radius of 12cm are ordered. If each student should get 50cm² of pizza, how many students can one pizza feed?
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Answer explanation
Area of pizza = πr² = π × 12² = 452.39 cm²
Number of students = 452.39 ÷ 50 ≈ 9.05
= 9 students
Tags
CCSS.HSG.C.B.5
4.
OPEN ENDED QUESTION
1 min • 2 pts
In Hobbiton, hobbit houses have circular windows. A hobbit needs to replace a window which has a circumference of 4.8 metres. What is the area of the window?
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Answer explanation
We need to find the radius first using the circumference formula:
C = 2πr
4.8 = 2πr
4.8 = 2 × 3.14 × r
r = 4.8 ÷ (2 × 3.14)
r = 0.764 metres
Calculate the area
A = πr²
A = 3.14 × (0.764)²
= 3.14 × 0.584
Tags
CCSS.7.G.B.4
5.
OPEN ENDED QUESTION
1 min • 2 pts
The school is painting a mural on a wall shaped like a trapezium. The parallel sides of the wall are 8 metres and 12 metres long, and the height between them is 5 metres. How much paint will they need if 1L covers 10 square metres?
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Answer explanation
Area of trapezium
= ½(a+b)h
= ½(8+12) × 5
= 50m²
Paint needed
= 50 ÷ 10
Tags
CCSS.6.G.A.1
6.
OPEN ENDED QUESTION
1 min • 3 pts
A church is commissioning a circular stained glass window with a smaller circular design in its centre. The outer circle has a radius of 2.4 metres, while the inner circle has an area that is 1/9 of the total window area. What is the radius of the inner circle?
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Answer explanation
Area of outer circle
= πr² = π(2.4)² = 18.1 m² (rounded to one dp)
Area of inner circle
=The inner circle's area is 1/9 of the total area
= 18.1 ÷ 9 = 2.01 m²
use the area formula for a circle to find the radius of the inner circle:
2.01 = πr²
r² = 2.01 ÷ π
r = √(2.01 ÷ π) ≈ 0.8 m
7.
OPEN ENDED QUESTION
1 min • 4 pts
A farmer notices a mysterious crop circle in his field. It's composed of two circles: a larger outer circle and a smaller inner circle. The area between the two circles is 200 square metres. If the radius of the larger circle is 10 metres, what is the radius of the smaller circle?
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Answer explanation
Area between circles
= π(R² - r²) = 200
= π(10² - r²) = 200
= 100π - πr² = 200
= πr² = 100π - 200
= r² = 100 - 200/π ≈ 36.34
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