Quadratic Equations by Square Root

For this quadratic equation, we said that there are NO REAL SOLUTIONS. Why did we say that?

• Because 3 goes into 9, so those cancel out

• Because we cannot take the square root of a negative number

• Because a has to be equal to 1

• Because there is no c value

Tags

CCSS.HSA-REI.B.4B

CCSS.HSN.CN.C.7

What is the error made when saving this quadratic equation?

• There should be 2 answers, because the square root of 9 is -3 and 3

• Taking the square root should always be the first step

• 21 -3 is not 18 so that was a mistake from the start

• The answer should be x = - 4 because the square root of 9 is -3

Tags

CCSS.HSA-REI.B.4B

What is the error made when solving this quadratic equation?

• The answer should only be -2 since the square root of -4 is -2

• The answer should only be 2, because the native cancels out, since we took the square root of a negative

• There is no error, everything was done correctly

• The answer should be no real solutions, since we can't take the square root of a negative

Tags

CCSS.HSA-REI.B.4B

CCSS.HSN.CN.C.7

Solve the equation using square roots.
x² = 121

• 60.5

• ± 11

• ± 12

• 11

Tags

CCSS.8.EE.A.2

x²=25

• x = 5

• x = -5

• x = ±25

• x = ±5

Tags

CCSS.8.EE.A.2

x²−10=19

• x = √29

• x = ±2√9

• x = ±29

• x = ±5√19

Tags

CCSS.8.EE.A.2

2x²= 30

• x= √5

• x= √30

• x= √15

• x= ±5

Tags

CCSS.8.EE.A.2

(x + 3)² = 36

• x = √36

• x = √39

• x = -9 and x = 3

• x = 9 and x = -3

Tags

CCSS.HSA-REI.B.4B

Solve using square roots.
5b² - 4 = 41

• b = 9, b = -9

• b = 3, b = -3

• b = 8, b = -8

• no solution

Tags

CCSS.8.EE.A.2

Solve using square roots.

k² - 6 = 43

• k = √37

• k = 37 or - 37

• k = 7, k = -7

• no real solution

Tags

CCSS.8.EE.A.2