Factoring and Solving Quadratic Equations Review

Factor:  3x² - 5x - 2

• (3x + 1)(x - 2)

• (3x + 2)(x - 1)

• (3x - 1)(x + 2)

• (3x - 2)(x + 1)

Factor:  8x² + 31x - 4

• (8x - 1)(x + 4)

• (4x - 1)(2x + 4)

• (2x - 1)(4x + 4)

• (8x - 2)(x + 2)

What are the solutions to this equation? (x-3)(x+2)=0

• x=3,-2

• x=-3,2

• x=2,3

• x=3,2

Tags

CCSS.HSA-REI.B.4B

When using factoring to solve a quadratic equation, what must be true?

• The equation must be set equal to 1.

• The equation must be set equal to 10.

• The equation must be set equal to 0.

• It is not necessary to set the equation equal to anything.

Tags

CCSS.HSA-REI.B.4B

Solve:
x² - 49 = 0

• x = -7, x = 7

• x = -7

• x = 7

• x = -7, x = 1

Tags

CCSS.8.EE.A.2

n² - 2n = 0

• n = 2 and 0

• n = -2 and 0

• n = 2

• n = 0

Tags

CCSS.HSA-REI.B.4B

What should you do first in solving this equation?
x² + 6x - 13 = 3

• Get factored form

• Find two numbers which add to make 6 and multiply to make -13

• Make it equal 0 by subtracting 3 on each side

• Type it all in a calculator.

Tags

CCSS.HSA-REI.B.4B

Factor:  x² - 16x + 24

• (x + 2)(x - 14)

• (x - 2)(x - 14)

• (x + 14)(x - 2)

• (x - 4)(x - 6)

Determine the values of

a, b, and c for

the quadratic equation:

4x² – 8x - 3 = 0

• a = 4, b = -8, c = 3

• a = 4, b =-8, c =-3

• a = 4, b = 8, c = 3

• a = 4, b = 8, c = -3

The solutions of the quadratic equation 
x²+2x-15=0 are

• x = 3 or x = 5

• x = 5 or x = -3

• x = -5 or x = 3

• x = -3 or x = -5

Tags

CCSS.HSA-REI.B.4B