Factoring Polynomials with GCF, Grouping, and Trinomials

• (2x + 1)(x + 15)

• (2x - 3)(x - 5)

• (x + 5)(2x + 3)

• 2(x - 3)(x - 5)

• prime

Hank factored 5n²-18n+9. His work is shown in the image. Is he correct? Why/why not?

• No, he set up the number puzzle wrong and found the wrong numbers that make the product and sum.

• No, he forgot to split the middle term using -15n and -3n to factor by grouping.

• Yes, those are the correct values to put into each factor.

• Yes, he's correct because he's a math teacher's son. ;)

• (4x - 5)(x + 5)

• (x - 5)(4x + 5)

• 4(x - 5)(4x + 5)

• 4(4x - 5)(x + 5)

Which number puzzle below shows how to set up the values correctly to factor a quadratic trinomial?

• 
• 
• 
• 

Factor:
10a⁴+16a+10a²

• 2a(5a³⁺8+5a)

• 2a⁴(5a+8a²+5a³)

• 2a⁴(10+16a+40a²)

• 3a³(5+8a+a²)

Factor by Grouping:
7r³-8r²+42r-48

• (r²+6)(7r+8)

• (r²+6)(7r-8)

• (r²+6)(r²+8)

• (r²+6)(7r+6)

Factor by Grouping:
20x³-25x²+4x-5

• (5x²-5)(4x+1)

• 5(x²-1)(4x+5)

• (5x²+1)(4x-5)

• (5x²+1)(4x-1)

Factor by Grouping:
30x³+15x²-18x-9

• (5x²-3)(6x+1)

• (5x²-3)(6x+3)

• 3(5x²+3)(2x-1)

• 3(5x²-3)(2x+1)

Factor this trinomial:
x²+10x+16

• (x+2)(x+8)

• (x-2)(x-8)

• (x+1)(x+16)

• (x+6)(x+10)