Special Cases of Factoring Polynomials

Completely factor this difference of squares x^2-100

Factor:
x² - 25

• ( x + 5 ) ( x - 5 ) 

• ( x - 5 ) ( x - 5 ) 

• ( x + 5 ) ( x + 5 ) 

• Prime

Factor:
x² - 16

• Prime

• ( x - 4) ( x + 4) 

• ( x - 8) ( x + 8) 

• ( x - 4) ( x - 4) 

Factor: 
x² - 225

• ( x + 15) ( x + 15) 

• Prime

• ( x - 15) ( x + 15) 

• ( x - 15) ( x - 15) 

In which scenario would you use the difference of squares formula to factor a polynomial?

• When the polynomial is a trinomial

• When the polynomial has four terms

• When the polynomial is a binomial with both terms perfect squares

• When the polynomial has a GCF other than 1

Factor: 
x² - 169

• ( x - 13) ( x + 13) 

• ( x + 13) ( x + 13) 

• ( x - 13) ( x -13) 

• Prime

Which of the following trinomials is a perfect square trinomial?

• r² - 6r + 36

• 4y² + 10y + 25

• x² + 16x + 16

• 9a² - 12a + 4

Factor:
x² - 30x + 225

• (x + 15)²

• (x - 15)²

• (x + 25)²

• (x - 25)²