Dividing Polynomials by Long Division and Synthetic

• x - 7
• x² - 7
• x + 7
• x² + 3x - 54

Tags

CCSS.HSA.APR.D.6

• x + 5 + (2/2x - 4)
• x - 8
• x - 5 + (3/2x - 4)
• x + 5

Tags

CCSS.HSA.APR.D.6

Divide using synthetic division 
(2x³ + 4x² - 5) by (x + 3).

• 2x² + 2x - 4  R(-12)

• 2x² - 2x + 6  R(-23)

• 2x² - 2x + 8  R(-20)

• 2x² - 4x + 1  R0

Tags

CCSS.HSA.APR.D.6

If you are missing a term in your polynomials (both dividend and divisor), you must put a zero as a coefficient place holder for that term.

• True

• False

• Only for the dividend

• Only for the divisor

Tags

CCSS.HSA.APR.D.6

Use synthetic division to divide the polynomial (5x^3 + 2x^2 - 4x + 1) by the binomial (x + 3).

• 5x^2 - 13x + 35 - 104/(x - 3)

• 5x^2 - 13x + 35 + 104/(x + 3)

• 5x^2 - 13x + 35 - 104/(x + 2)

• 5x^2 - 13x + 35 - 104/(x + 3)

Tags

CCSS.HSA.APR.D.6

• A

• B

• C

• D

Tags

CCSS.HSA.APR.D.6

Identify the missing term to complete the solution.

• 28

• 38

• 48

• 58

Tags

CCSS.HSA.APR.D.6

Use synthetic division to divide the polynomial (2x^3 + 4x^2 - 3x + 1) by the binomial (x - 1).

• 2x^2 + 6x - 3

• 2x^2 + 4x + 3

• 2x^2 + 2x + 3

• 2x^2 + 6x + 3

Tags

CCSS.HSA.APR.D.6

Use synthetic division:
(2x³ - 5x - 7) ÷ (x - 2)

• 2x³ - 4x² + 3x - 13

• 2x³ + 4x² +3x - 1

• 2x² - 4x + 3 - 13/x-2

• 2x² + 4x + 3 - 1/x-2

Tags

CCSS.HSA.APR.D.6

• x+7

• x+2

• X-10

• X-7

Tags

CCSS.HSA.APR.D.6