Infinite Precalculus: Dividing Polynomials

Which would be better to use here?

• Long division

• Synthetic division

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CCSS.HSA.APR.D.6

Divide (4x³ - 2x² - 3) by (2x² - 1).

• 2x - 1 + (2x - 4)/(2x² - 1)

• 2x + 3 + (x - 3)/(2x² - 1)

• 2x - 1

• 2x + 3 + (3x-5)/(2x² - 1)

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CCSS.HSA.APR.D.6

• 2x - 5

• x - 4 + 3/(4x - 5)

• 2x + 4 + 3/(4x - 5)

• 2x + 4

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CCSS.HSA.APR.D.6

Find the quotient when (21x² - 52x + 32) is divided by (7x - 8).

• 3x + 4

• 3x + 3

• 3x - 4

• 3x + 2

Tags

CCSS.HSA.APR.D.6

Find the quotient

Mathematical Equivalence

ON

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CCSS.HSA.APR.D.6

(4x⁴ - 3x³ - 4x² - x + 3)/(4x - 3)

• x³ + x² + x - 1

• x³ - x - 1

• x³ - 2x - 1

• x³ - x² + x - 3

Tags

CCSS.HSA.APR.D.6

Divide:

(4x² - 24x + 35) / (2x - 5)

• 2x - 7

• 2x - 12

• 2x + 12

• 2x + 7

Tags

CCSS.HSA.APR.D.6

For synthetic division, what would be the number in the left hand box?

• 0

• 1

• 2

• 3

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CCSS.HSA.APR.D.6

Divide using synthetic division

(2x³ + 4x² - 5) by (x + 3).

• 2x² + 2x - 4 - 12/(x + 3)

• 2x² - 2x + 6 - 23/(x + 3)

• 2x² - 2x + 8 - 20/(x + 3)

• 2x² - 4x + 1

Tags

CCSS.HSA.APR.D.6

2x³ - 5x² + 3x + 7 ÷ x - 2

• 2x³ - x² + x + 9

• 2x² - x + 1

• 2x² - x + 1 + 9/(x - 2)

• 2x² - 9x - 15 - 23/(x - 2)

Tags

CCSS.HSA.APR.D.6