Estimating Crowds

ON GRAPHIC ORGANIZER - Maynard Jackson is expecting 500 people to be at the Homecoming Dance. If we are estimating that 10 people can fit in every 25 square feet, how much area will be needed for the dance?

• 200 square feet

• 1250 square feet

• 2000 square feet

• 5000 square feet

If 10 people can fit in a 30 square foot area, how many people can fit in a 300 square foot area?

• 200

• 100

• 30

• 50

If there are 40 people in a 100 square foot area, what is the estimated number of people that can fit in a 1,000 square foot area?

• 40

• 400

• 10

• 100

One rule of thumb for estimating crowds is that each person occupies 2.5 square feet. Use this rule to estimate the size of the crowd watching a concert in an area that is 150 feet long and 240 feet wide.

• 156 people

• 35,031 people

• 5,760 people

• 14,400 people

One rule of thumb for estimating crowds is that ten people occupies 5 by 5 ft2.  Use this rule to estimate the crowd standing 2 miles long 3 feet deep

• crowd = [10/5] x [2 x 3]

• crowd = [10/25] x [2 x 3]

• crowd = [10/25] x [2 x 3 x 5280]

• crowd = 2 x [10/25] x [2 x 3 x 5280]

One rule of thumb for estimating crowds is that ten people occupies 5 by 5 ft2.  Use this rule to estimate two sides of the road (crowds of 2) standing 2 miles long 3 feet deep.

• 2 Crowd = [10/5] x [2 x3]

• 2 Crowd = [10/25] x [2 x3]

• 2 Crowd = [10/25] x [2 x3 x 5280]

• 2 Crowd = 2x [10/25] x [2 x3 x 5280]

12 people fit comfortably in a 5 feet by 5 feet area. Use this value to estimate the size of a crowd that is 25 feet deep on both sides of the street along a 3-mile section of a parade route. (Hint: 1 mile = 5,280 ft)

• 264,000 people

• 380,160 people

• 158,400 people

• 2,534 people

15 people fit comfortably in a 6 feet by 6 feet area. Use this value to estimate the size of a crowd that is 30 feet deep on both sides of the street along a 2-mile section of a parade route. (Hint: 1mile= 5,280ft)

• 264,000 people

• 132,000 people

• 190,080 people

• 2,534 people