Find the Center and Radius of the Given Equation of Circle

What is the radius of the circle given by the equation (x - 7)² + (y + 3)² = 25?

• 3

• 5

• 10

• 25

Tags

CCSS.HSG.GPE.A.1

What is the radius of the circle with equation x² + y² = 1?

• 0

• 0.5

• 1

• 2

Tags

CCSS.HSG.GPE.A.1

What is the radius of the circle with this equation of (x - 5)² + (y + 7)² = 8?

• 4

• 8

• 4√2

• 2√2

Tags

CCSS.HSG.GPE.A.1

What is the radius of the circle with this equation x² + y² - 10x + 8y - 23 = 0?

• 4

• 2

• 8

• 23

Tags

CCSS.HSG.GPE.A.1

Determine the equation of the circle in standard form: x² + y² + 4x + 6y - 36 = 0

• (x + 2)² + (y + 3)² = 49

• (x + 2)² + (y + 3)² = 13

• (x - 2)² + (y - 3)² = 49

• (x - 2)² + (y - 3)² = 13

Tags

CCSS.HSG.GPE.A.1

Write the standard equation of the circle with the given center and radius; center (0, 0) and radius of 3.

• x² + y² = 4

• x² + y² = 81

• x² + y² = 9

• x² + y² = 3

Tags

CCSS.HSG.GPE.A.1

Change the following equation to standard form

• (x + 2)² + (y - 6)² = 48

• (x - 2)² + (y + 6)² = 48

• (x - 6)² + (y - 2)² = 48

• (x + 2)² + (y - 6)² = 48

Tags

CCSS.HSG.GPE.A.1

In the equation (x-3)²+(y-2)²=16, the center of the circle is...

• (3,2)

• (-3, -2)

• (-2, -3)

• (2, 3)

Tags

CCSS.HSG.GPE.A.1

In the equation (x+2)²+(y-3)²=4, the radius of the circle is...

• 4

• 2

• 3

• 16

Tags

CCSS.HSG.GPE.A.1

In the equation (x-4)²+(x-3)²=25, the center of the circle is at...

• (-3, -4)

• (4, 3)

• (-4, -3)

• (3, 4)

Tags

CCSS.HSG.GPE.A.1