Find the Center and Radius of the Given Equation of Circle

Identify the CENTER and RADIUS for the following circle:

x² + y ² = 324

• Center: (0,0) Radius: 12

• Center: (1,1) Radius: 10

• Center: (0,0) Radius: 18

• Center: (1,2) Radius: 25

Tags

CCSS.HSG.GPE.A.1

In the equation (x - 3)² + (y - 2)² = 16, the center of the circle is...

• (3,2)

• (-2, -3)

• (-3, -2)

• (2, 3)

Tags

CCSS.HSG.GPE.A.1

In the equation (x + 2)² + (y - 3)² = 4, the radius of the circle is...

• 4

• 3

• 2

• 16

Tags

CCSS.HSG.GPE.A.1

In the equation (x - 4)² + (x - 3)² = 25, the radius is...

• 4

• 5

• 3

• 25

Tags

CCSS.HSG.GPE.A.1

What is the center of the circle with this equation is (x + 2)² + (y - 4)² = 41?

• (2,-5)

• (2,-4)

• (-2,4)

• (-2, -4)

Tags

CCSS.HSG.GPE.A.1

In order to convert from general form to center-radius form, you must ___________. 

• Multiply out

• expand

• factor

• complete the square

Tags

CCSS.HSG.GPE.A.1

Determine the equation of the circle in standard form: x² + y² + 6x - 12y + 20 = 0

• (x-3)² + (y+6)² = 25

• (x+3)² + (y-6)² = 25

• (x-3)² + (y+6)² = 45

• (x+3)² + (y-6)² = 5

Tags

CCSS.HSG.GPE.A.1

Determine the equation of the circle in standard form:
x² + y² + 4x + 6y - 36 = 0

• (x+2)² + (y+3)² = 49

• (x+2)² + (y+3)² = 13

• (x-2)² + (y-3)² = 49

• (x-2)² + (y-3)² = 13

Tags

CCSS.HSG.GPE.A.1

What is the radius of the given circle:
 x²+y²-10x+8y-23=0?

• 4

• 2

• 8

Tags

CCSS.HSG.GPE.A.1

Identify the center and the radius of the circle in general form.

• A

• B

• C

• D

Tags

CCSS.HSG.GPE.A.1