Solving Quadratics by Factoring

Which of these quadratics is NOT Factorable.

What should you do first in solving this equation?

x² + 6x - 13 = 3

• Get factored form

• Write down: a=1, b=6, c=-13

• Make it equal 0 by subtracting 3 on each side

• Type it all in a calculator.

Solve by factoring:
x² - 6x + 5 = 0

• -6, -1

• -5, -1 

• 1, 6

• 5, 1

Solve by factoring.
z² - 6z - 27 = 0

• z = 3 or z = 9

• z = 3 or z = -9

• z = -3 or z = 9

• z = -3 or z = -9

Solve by factoring.
z² - 18z + 81 = 0

• z = 9

• z = -9

• z = 9 or z = -9

Solve:

k² - 2k - 24 = 0

• k = -4, 6

• k = -4, -6

• k = -6, 1

• k = 4, -6

Solve for the values of x:
(x - 3)(x + 6) = 0

• { -3, -6 }

• { 3, -6 }

• { -3, -6 }

• { 3, 6 }

Solve using Zero-Product Property.
(x+4)(x-3) = 0

• x = 4 and x = -3

• x = 2 and x = 1

• x = -4 and x = 3

• x = -2 and x = 1

Solve
x² + 2x - 24 = 0

• x = -6, x = 4

• x = 6, x = -4

• x = 12, x = -2

• x = 8, x = -3