Sample Z Test for Proportion

USA Today reported that in 1992, 39% of all elementary school children claimed that when they grow up they want to do something to help other people. However, in 1995, 128 of a random sample of 317 of these same children claimed that when they grow up they want to do something to help other people. Does this information indicate that there has been an attitude change either way?

• One-Sample Z Test for a Proportion

• Two-Sample Z Test for the Difference in Proportions

• One-Sample T Test for a Mean

• Two-Sample T Test for the Difference in Means

The manufacturer of a particular brand of microwave popcorn claims that only 2 percent of its kernels of corn fail to pop. A competitor, believing that the actual percentage is larger, tests 2,000 kernels and finds that 44 failed to pop. Do these results provide sufficient evidence to support the competitor's belief?

• One-Sample Z Test for a Proportion

• One-Sample T Test for a Mean

• Two-Sample Z Test for a Proportion

• Matched-Pairs T Test for a Mean

Conduct a test to determine whether or not the population proportion of voters in favor of proposal A is greater than 50%. In a random sample of 200 voters, 140 said that they were in favor of this proposal. Compute the test statistic.

• z = 6.17

• z = 5.66

• z = 19.80

• None of the above

Which of the following hypotheses is a valid example of a 1-tailed test?

• Ho: p = 0.3, Ha: p > 0.4

• Ho: p = 0.3, Ha: p ≠ 0.3

• Ho: p^ = 0.3, Ha: p^ > 0.3

• Ho: p = 0.3, Ha: p > 0.3

• A

• B

• C

• D

• E

Select the correct description

• Average Percent

• Population Proportion

• Sample Proportion

• Percent Slope of a Distribution

According to the Center for Disease Control, 93% of children entering kindergarten in the U.S. are vaccinated. Find the z-score associated with a sample of 180 children in which 162 have been vaccinated.

• -1.34

• 1.34

• .0901

• .9099

According to Pew Research, about 63% of American adults are working from home by choice. Suppose you survey a random sample of 600 American adults and ask if they are working from home by choice. What proportion of your sample would you expect to say yes? ​ Compute the standard error for your sample proportion. ​ Calculate the z-score for a sample proportion of 58%. ​ Would it be surprising to obtain a sample proportion of 58%? ​ ​

• 63%

• 0.0197

• -2.54

• Yes, it is outside of 2 SE

• No, it is within reason

• 1.971

• 37%

• 50%

​ (a)   is a population proportion. ​ (b)   is a sample statistic.

• p

• p̂

A test was conducted to see if there was evidence that more than 10% of the population is left-handed. Ho: p = 0.10, Ha: p >0.10. A p-value of 1.10 is found. What can we conclude?

• There is not evidence that more than 10% of people are left-handed

• We can conclude that more than 10% of people are left-handed

• There is evidence that more than 10% of people are left-handed

• The person who ran this test made an error