Perpendicular Bisector Equation

Write the equation of the perpendicular bisector that goes through the line segment with end points of ( 10, -10 ) and B ( 2 , 2 ).

• y=(-3/2)x - 8

• y=(2/3)x-8

• y=(2/3)x+8

• y=(-3/2)x-8

Find the equation of the perpendicular bisector PQ for the given endpoints. P(5,2) and Q(7,4)

• y=x-6

• y=x+6

• y=x+9

• y=-x+9

Find the equation of the perpendicular bisector for the given endpoints. (-3,9) and (-1,5)

• y=(-1/2)x+8

• y=(1/2)x+8

Tags

CCSS.HSG.CO.A.1

Given you have two points and are asked to find the perpendicular bisector, what step should you do first?

• Skip the problem

• Find the slope

• Find the equation of the line

• Find the midpoint

Tags

CCSS.HSG.CO.C.9

Write the equation of the perpendicular bisector of the line AB given: A(-4,3) & B(4,3). Hint: After you find the equation make sure it is in y = form. Get y or x by itself

• x = 3

• y = 0

• y = x

• x = 0

Tags

CCSS.HSG.CO.C.9

What geometric construction is shown in the diagram below?

• an angle bisector

• a line parallel to a given line

• an angle congruent to a given angle

• a perpendicular bisector of a segment

Tags

CCSS.HSG.CO.C.9

Write the equation of the perpendicular bisector that goes through the line segment with end points of ( 9, 5 ) and B ( -7 , 13 ).

• y=2x+7

• y=2x-17

• y=(-1/2)x + 7

• y=(2)+7

Tags

CCSS.HSG.CO.C.9

If you found the midpoint of line segment AB, what should you do next to find the equation of the perpendicular bisector?

• Use the midpoint and one of the points from AB to write the equation

• Use the midpoint and slope perpendicular to AB to write the equation

• Use the distance and midpoint to find the equation

• Skip it and hope it's not a test question

Tags

CCSS.HSG.CO.C.9

Write the equation of the perpendicular bisector of the line AB given:
A(3,1) & B(-3,6)

• y = -5/6x + 7/2

• y = 6/5x + 9/2

• y = 6/5x + 7/2

• y = 6/5x + 4

Write the equation of the perpendicular bisector of the line AB given:
A(-4,3) & B(4,3)

• y = 3

• x = 0

• y = x

• y = 0