Law of Sines and Area of Triangles

What is the area of this triangle?

• 14.494 meters squared

• 108.184 meters squared

• 54.092 meters squared

• 54.35 meters squared

Tags

CCSS.HSG.SRT.D.9

Find the area:

• 104.5 units²

• 120 units²

• 80.5 units²

• 2400 units²

Tags

CCSS.6.G.A.1

What is this Triangle's area?

• 8.0

• 17.9

• 80.0

• 8.97

Tags

CCSS.HSG.SRT.D.9

Which area formula works for this triangle?

• ½(5)(7)cos(49⁰)

• (5)(7)sin(49⁰)

• ½(5)(7)sin(49⁰)

• all of these

Tags

CCSS.HSG.SRT.D.9

Which formula would you use?

• Law of Sines

• Law of Cosines

• Herons

• A=.5acsinB

Tags

CCSS.HSG.SRT.D.10

CCSS.HSG.SRT.D.11

Solve each triangle. A=110, C=30, c=3

• B=40, a=5.64, b= 3.86

• B= 45, a= 6.93, b= 2.76

• B= 40, a= 7.90, b= 3.41

• B=40, a= 6.21, b= 3.86

Tags

CCSS.HSG.SRT.D.10

CCSS.HSG.SRT.D.11

Find AC

• 12

• 10

• 23

• 14

Tags

CCSS.HSG.SRT.D.10

CCSS.HSG.SRT.D.11

Parker must find the distance from Point A to Point B on opposite sides of a lake.  He locates Point C that is 860 feet from point A and 175 feet from Point B.  He measures the angle at Point C to be 78 degrees.  Find the distance from point A to point B.

• 707643.58

• 841.22

• 877.62

• 842.01

Tags

CCSS.HSG.SRT.D.10

CCSS.HSG.SRT.D.11

Given: B = 70°, a = 11, C = 40° Find: c

• 11

• 7.5

• 70

• 8

Tags

CCSS.HSG.SRT.D.10

CCSS.HSG.SRT.D.11

Solve the Triangle
a=38, b= 31, c= 35
Find A, B and C

• A= 43°, B= 47°, C= 90°

• A= 70°, B= 50.1°, C= 59.9°

• A= 50.1°, B= 70°, C= 59.9°

• A= 60°, B= 70°, C= 50°

Tags

CCSS.HSG.SRT.D.10

CCSS.HSG.SRT.D.11