Solving Polynomials by Synthetic Division

What is the first step in solving using synthetic division

• Factor the Polynomial

• Divide by 7

• Solve for n in the denominator

• Solve for n in the numerator

Tags

CCSS.HSA.APR.D.6

Using synthetic division what is the constant term?

• 20

• 8

• 14

• 9

Tags

CCSS.HSA.APR.D.6

Cam divided (x⁴ + 3x² - 4x - 2) by factor of (x-2) using synthetic division. His work is shown above. Which best describes his mistake?

• Cam wrote the remainder incorrectly.

• Cam did not use a zero place holder for the x³ term.

• Cam added instead of subtracting the rows.

• Cam should have used -2 as his division since the factor was x-2.

Tags

CCSS.HSA.APR.D.6

• x=-3, 3

• x=-3,-2,2,3

• x=36

• x=2,-2

Tags

CCSS.HSF-IF.C.7A

Divide using synthetic division

(2x³ + 4x² - 5) by (x + 3).

• 2x² + 2x - 4 - 12/(x + 3)

• 2x² - 2x + 6 - 23/(x + 3)

• 2x² - 2x + 8 - 20/(x + 3)

• 2x² - 4x + 1

Tags

CCSS.HSA.APR.D.6

Divide using synthetic division 
(2x³ + 4x² - 5) by (x + 3).

• 2x² + 2x - 4  R(-12)

• 2x² - 2x + 6  R(-23)

• 2x² - 2x + 8  R(-20)

• 2x² - 4x + 1  R0

Tags

CCSS.HSA.APR.D.6

Use synthetic division to divide the polynomial (5x^3 + 2x^2 - 4x + 1) by the binomial (x + 3).

• 5x^2 - 13x + 35 - 104/(x - 3)

• 5x^2 - 13x + 35 + 104/(x + 3)

• 5x^2 - 13x + 35 - 104/(x + 2)

• 5x^2 - 13x + 35 - 104/(x + 3)

Tags

CCSS.HSA.APR.D.6

Tags

CCSS.HSA.APR.D.6

Use synthetic division to divide the polynomial (2x^4 - 5x^3 + 3x^2 + 4x - 1) by the binomial (x + 1).

• 2x^3 - 7x^2 + 10x - 1

• 2x^3 - 7x^2 + 10x + 6

• 2x^3 - 7x^2 + 10x + 1

• 2x^3 - 7x^2 + 10x - 6

Tags

CCSS.HSA.APR.D.6

Use synthetic division to divide the polynomial (2x^3 + 4x^2 - 3x + 1) by the binomial (x - 1).

• 2x^2 + 6x - 3

• 2x^2 + 4x + 3

• 2x^2 + 2x + 3

• 2x^2 + 6x + 3

Tags

CCSS.HSA.APR.D.6