Solving Logarithmic Equations and Exponential Equations

• A
• B
• C
• D

ln (3x + 2) = ln (5x - 6)

• x = 1

• x = 4

• x = 2

• x = 7

log₂ x + log₂ (x + 5) = log₂ (3x + 8)

• x = 2

• x = -4

• x = 2 and x = -4

• no solution

Solve: log₃ (5) + log₃(x) = log₃(2) + log₃(x + 9)

• 5

• 11

• 6

• 3

Rewrite the equation in logarithmic form.

• A

• B

• C

• D

Tags

CCSS.HSF.BF.B.5

Rewrite in exponential form.

• A

• B

• C

• D

Tags

CCSS.HSF.BF.B.5

log₂(x² - 6) = log₂(2x+2)

• 4, -2

• No Solution

• 4

• -2

Rewrite the equation in logarithmic form.

• A

• B

• C

• D

Tags

CCSS.HSF.BF.B.5

To evaluate a logarithm statement log₉81, you think "9 to what power is 81".

• True, and it's 2

• False

Tags

CCSS.HSF.BF.B.5

Evaluate the log:
log₃(1/9) = 

• 1/2

• 2

• -2

• 3