
Chapter 11 AP Statistics
Authored by Anthony Clark
Mathematics
12th Grade

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1.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
The Gallup Poll asked a random sample of 1785 adults whether they attended church during the past week. Let p-hat be the proportion of people in the sample who attended church. A newspaper report claims that 40% of all U.S. adults went to church last week. Suppose this claim is true.
What is the mean of the sampling distribution of p-hat?
0.4
0.44
0.56
0.6
2.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
Which best describes the sampling distribution shown below.
Unbiased Estimator
Biased Estimator
3.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
Would it be unusual to get a sample proportion of .35 or higher? Explain
Yes because only 10 of the sample proportions 0.35.
No because 23/100 of the sample proportions were 35% or higher. 23% is not unusual
Yes because we should get 25% every time.
4.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
Would it be unusual to get a sample proportion of .60 or higher? Explain
Yes because only 1 out the 100 sample proportions was 60%. 0.01 is unusual.
Yes because if it is possible, it can't be unusual.
5.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
Sampling distributions were created with 3 different sample sizes of 10, 50, and 100. Which sampling distribution goes with which sample size?
Curve 1: 10
Curve 2: 50
Curve 3: 100
Curve 1: 50
Curve 2: 10
Curve 3: 100
Curve 1: 100
Curve 2: 50
Curve 3: 10
Curve 1: 10
Curve 2: 100
Curve 3: 50
6.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
The sampling distribution of a statistic is shown which has a mean of 4.5. The population parameter is 4.5. Is the statistic an unbiased estimator?
Yes because the mean of the sampling distribution is equal to the parameter
Yes because sampling distribution is skewed right
No because the sampling distribution is skewed right
No because there is a lot of variability in the sampling distribution
7.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
A candy maker offers child- and adult size bags of jelly beans with different color mixes. The company claims that the child mix has 30% red jelly beans, while the adult mix contains 15% red jelly beans. Assume that the candy maker’s claim is true. Suppose we take a random sample of 50 jelly beans from the child mix and a separate random sample of 100 jelly beans from the adult mix. Let p̂1 and p̂2 be the sample proportions of red jelly beans from the child and adult mixes, respectively. Calculate the standard deviation of the sampling distribution for the difference in proportions.
0.0740
0.0648
0.0357
You can't calculate the standard deviation.
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