Solving Two Variable System of Equations

In this system

x+3y=9

4x-2y=-6

it'll be easiest to start by solving the first equation for x.

The result of doing so is x=​9-3y.

Fill in the blanks to plug that expression in and solve for y:

4(​9-3y)-2​y =-6

36-​12y-2y=​-6

36-​14y =-6

-14y=​ (a)  

y=​ (b)  

• -42

• 3

• 30

• -3

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

Put the steps for solving by ELIMINATION in order:

• Plug that number into either original equation and solve for the other variable

• Solve for the remaining variable

• Multiply one or both equations by a number to get common but opposite coefficients

• Subtract the equations to eliminate one variable

• Make sure the equations are lined up

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

In this system

x+3y=9

4x-2y=-6

we have figured out that x=9-3y, and y=3.

Complete the steps to solve for x:

x=9-3(​ (a)   )

x=9-​ (b)  

x=​ (c)  

The solution to the system is (​ (d)   ,​ (e)   ).

• 3

• 9

• 0

• y

• x

• y=3

• 3y

• -9

• 18

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

Consider the system

4x+3y=-1

5x+4y=1

Let's say I want to eliminate the y's. What is the least common multiple of 3 and 4?

LCM = ​ (a)  

Multiply each equation by a number so that the coefficient of y will be 12, with one positive and one negative.

​ (b)   (4x+3y=-1)

​ (c)   (5x+4y=1)

• 12

• 4

• -3

• 3

• 5

• 1

• -1

• -12

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

Consider the system

4x+3y=-1

5x+4y=1

After we do this multiplication, what will the new equations be?

​ 4(4x+3y=-1) ---> ​ (a)   x +​ (b)   y=​ (c)  

​-3(5x+4y=1)​ ---> ​ (d)   x -​ (e)   y= -3

• 16

• 12

• -4

• -15

• 3

• 5

• 1

• -1

• -12

• -3

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

Consider the system:

4x+3y=-1

5x+4y=1

Which we converted to:

16 x +​ 12y=​-4

-15x -​ 12y= -3

Combining the equations straight down gives us:

​ (a)   x+​ (b)   y=​ (c)  

Solving for x, we get x=​ (d)  

• 1

• 0

• -7

• 3

• 5

• -1

• -12

• -3

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

Consider the system:

4x+3y=-1

5x+4y=1

Since we now know that x=-7, solve for y:

4(​ (a)   )+3y=-1

​ (b)   +3y=-1

​ (c)   =​ (d)  

y=​ (e)  

• -7

• -28

• 3y

• 27

• 9

• 5

• 7

• -12

• 3

• y

Tags

CCSS.HSA.REI.C.9

Graph both equations on the same coordinate plane.

y=4x-3

y=-3x+4

Tags

CCSS.8.EE.C.8B

How many solutions does the graph have?

• One solution

• No solution

• Infinite solutions

Answer explanation

These lines intersect at ONE point. This means that only one point will be true for the equations of both lines.

Tags

CCSS.8.EE.C.8B

Which answer has a correct first step for solving this system without graphing:

• The variable is already isolated, so we've already solved the system.

• The variable is already isolated for y, so we substitute it in the first equation and solve for x

  3x + 3(3x + 5) = 3

• Free sha vaca doo

• The variable is already isolated for y, so we substitute it in the second equation and solve for x

  y = 3(3x + 3y) = 3

Answer explanation

$3x+3y=3$

$y=3x+5$
A variable is already isolated here, so we already have an equivalent expression from the second equation that can be substituted in place of y in the first equation.

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6