Solving Systems of Equations Using Ordered Pairs

Solving Systems of Equations Using Ordered Pairs

9th Grade

15 Qs

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Solving Systems of Equations Using Ordered Pairs

Solving Systems of Equations Using Ordered Pairs

Assessment

Quiz

Mathematics

9th Grade

Hard

CCSS
8.EE.C.8B, HSA.REI.C.7, HSA.CED.A.3

+3

Standards-aligned

Created by

Anthony Clark

FREE Resource

15 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Solve the system of equations below:

4x+9y=28

-4x-y=-28

(-7,0)

(6,0)

(-6,0)

(7,0)

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

2.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Which method would be best (quickest) for solving the system below:
x + y = 11
3x - 4y = -2

Substitution

Elimination

Graphing

None of these

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

3.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Which method would be best (quickest) for solving the system below:
3x - 4y = -2
y = 2x + 1

Substitution

Elimination

Graphing

None

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

4.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Solve by elimination:

7x+y=-9


-3x-y=5

No solution

(1,8)

(-1,-3)

(-1,-2)

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

5.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Solve the system:
2x - 5y = 12
y = -2

y = -2

(11, -2)

(1, -2)

no solution

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

6.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Christian had brochures printed for a new business venture. Christian originally ordered 4 boxes of black-and-white brochures and 3 boxes of color brochures, which cost a total of $134. After those ran out, Christian spent $120 on 3 boxes of black-and-white brochures and 3 boxes of color brochures. Which system represents this situation?

x+y=134
x+y=120

3x+3y=134
4x+3y=120

4x+3y=134
3x+3y=120

7xy=134
6xy=120

Tags

CCSS.HSA.CED.A.3

7.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

The talent show committee sold a total of 530 tickets in advance. Student tickets cost $3 each and the adult tickets cost $4 each. If the total receipts were $1740, how many of each type of ticket were sold?

S + A = 530
3S + 4A = 1740

S + A = 530
4S + 3A = 1740

S + A = 1740
3S + 4A = 530

S + A = 1740
4S + 3A = 530

Tags

CCSS.8.EE.C.8C

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