Test Review of Solving Systems

Solve the system by elimination.
4x + 12y = −1
−3x − 9y = 0 

• (10, 1) 

• (−10, −1) 

•  (10, −1) 

•  No solution 

Tags

CCSS.8.EE.C.8B

Solve using elimination.
−4x − 4y = 0
8x + 8y = 0

• (−6, −4) 

• Infinite number of solutions  

• No solutions

• (6, 4) 

Tags

CCSS.8.EE.C.8B

Homer sells tickets for admission to your school play and collects a total of $104. Admission prices are $6 for adults and $4 for children. He sold 21 tickets total. Solve the system:
x + y = 21
6x + 4y = 104

• (10, 11)

• (12, 9)

• (11, 10)

• (9, 12)

Tags

CCSS.8.EE.C.8C

What is the first step in solving a system of equations by elimination?

• Get both equations in standard form and line up the like terms.

• Get both equations in slope-intercept form.

• Get both equations equal to zero.

• Put the x terms first.

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

What does the top equation need to be multiplied by to eliminate a variable?

• -1

• 1

• -2

• 2

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

________________ are two or more equations that have the same variables and exponents

• graphing lines

• elimination method

• system of equations

• table

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

What should we do next to solve for the x coordinate of the point?

• Get x by itself by subtracting 3.

• Cry

• Additive Inverse

• Divide both sides by 3 to make a ghost one.

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

When you solve these two equations together, what is the resulting equation?

x - 2y = 3

-x - 4y = 9

• 0x - 6y = 12

• -2x + 6y = 12

• 6x = 12

• Don't know. :(

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

When you solve these two equations together, what is the resulting equation?

2y = 2x + 2

y = -2x - 5

• y = -1

• 3y = 4x + 3

• y = 0x - 3

• 3y = -3

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

What does it mean to "solve a system of equations?"

• To write equations in slope intercept form.

• To solve for x.

• To find coordinates of a point where lines cross.

• To do math stuff that is extremely hard and I'll never understand it so I'm just going to give up.

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6