Solving for Vertex and Axis of Symmetry

Identify the vertex of the parabola y = 2x^2 - 8x + 6.

• The vertex is (-2, 10)

• The vertex is (4, -6)

• The vertex is (0, 6)

• The vertex is (2, -2)

Find the axis of symmetry for the parabola y = -2x^2 + 6x - 4.

• x = -b/(2a)

• x = -b/(2a) + 2

• x = -b/(2a) - 3

• x = -b/(2a) + 1

Find the axis of symmetry for the parabola y = 4x^2 - 16x + 15.

• x = 4

• y = 2

• x = 2

• x = -2

Find the axis of symmetry for the parabola y = -x^2 + 8x - 16.

• x = 4

• x = -4

• x = 2

• x = 6

For the given graph, find

Vertex = ​ (a)  

Axis (line) of symmetry ​ (b)  

• x=-4

• (-3,-1)

• (3, -1)

• x=-3

• x=3

• (-4, -2)

The vertex of the graph is ​ (a)   and the axis of symmetry is ​ (b)   .

The function has a ​ (a)   with a value of ​ (b)   and the equation for the axis of symmetry is ​ (c)  

• minimum

• -5

• x=-3

• y=-5

• maximum

• -3

• -4

• 4

• x=-5

• x=3

• (1,3)

• (-1,-3)

• (1,-3)

• (-1,3)

• (-3,1)

• (3,1)

• (-3,-1)

• x=1

• x=-1

• x=-3

The vertex is ​ (a)   and the axis of symmetry is ​ (b)  

• (-2,-3)

• x = -2

• (-3,-2)

• y = -2

• x = 3

• y = -3

• (-2,3)

The vertex of the parabola is at ​ (a)   . This means there is a ​ (b)   value at ​ (c)  

• (1,5)

• Maximum

• y = 5

• (5, 1)

• Minimum

• y = 1

• (0, 4)