Solve Systems of Equations Substitution

Which answer has a correct first step for this system:

• The variable is already isolated, so we've already solved the system.

• The variable is already isolated for y, so we substitute it in the first equation and solve for x

  3x + 3(3x + 5) = 3

• Free sha vaca doo

• The variable is already isolated for y, so we substitute it in the second equation and solve for x

  y = 3(3x + 3y) = 3

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

Solve this system using substitution

• (1, -2)

• (2, -2)

• (1, 2)

• Why have you done this?

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

Solve with substitution

x = -3y - 8

x - 2y = -3

• (5, -1)

• (-5, 1)

• (-5,-1)

• (1,-5)

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

What is the solution to this system?
2x + 3y = 4
y= 5x - 27

• (5,-2)

• (5, 2)

• (2,3)

• (3,2)

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

What does
"solution to a system of equations"
mean?

• It's the point where both equations equal zero

• It's the point where graphs of both equations cross the y-axis

• It's the point that solves both equations at the same time

• It's the point where graphs of both equations cross the x-axis

Tags

CCSS.8.EE.C.8B

Solve:
y=8x+1
y=6x+3

• (1, 9)

• (4, 14)

• (0, 1)

• (2, 4)

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

Solve for x and y by using the substitution method.

y = 2x + 1

y = 4x - 1

• (1, 3)

• (-1, -3)

• (-1, 3)

• (3, 1)

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

Solve for x and y by using the substitution method. 3x + 2y = 16 y = -7x + 19

• (-2, 5)

• (-2, -5)

• (2, -5)

• (2, 5)

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

Solve the system by using the substitution method.

x = 3y + 1

2x + 4y = 12

• (4, 1)

• (1, 4)

• (3, 1)

• (1, 3)

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

Solve for x and y using the substitution method.

5x + 3y = 7

y = 4

• (4, 1)

• (4, -1)

• (1, 4)

• (-1, 4)

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6