Modeling Exponential Functions Percent Growth Decay

Modeling Exponential Functions Percent Growth Decay

9th Grade

20 Qs

quiz-placeholder

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Modeling Exponential Functions Percent Growth Decay

Modeling Exponential Functions Percent Growth Decay

Assessment

Quiz

Mathematics

9th Grade

Hard

CCSS
HSF.LE.A.2, HSF-IF.C.7E, HSF-BF.A.1A

+4

Standards-aligned

Created by

Anthony Clark

FREE Resource

20 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Marilyn collects old dolls. She purchases a doll for $450. Research shows this doll's value will increase by 2.5% each year. Write an equation that determines the value, V, of the doll t years after purchase.

V = 450(1 + 0.025)t

V = 450(1 – 0.025)t

V = 450(1 + 2.5)t

V = 450(1 – 2.5)t

Tags

CCSS.HSF.LE.A.2

2.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

A car was purchased for $25,000. Research shows that the car has an average yearly depreciation rate of 18.5%. Create a function that will determine the value, V(t), of the car t years after purchase.

V(t) = 25000(1 – 0.185)t

V(t) = 25000(1 + 0.185)t

V(t) = 25000(1 – 18.5)t

V(t) = 25000(1 + 18.5)t

Tags

CCSS.HSF.LE.A.2

3.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

The population of a town is currently 6342 and is increasing by a rate of 1.3% each year. Which function represents the population of people, P, after t years.

P = 6342(1 + 1.3)t

P = 6342(1 – 1.3)t

P = 6342(1 + .013)t

P = 6342(1 – .013)t

Tags

CCSS.HSF.LE.A.2

4.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

An antibiotic is introduced into a colony of 12,000 bacteria during a laboratory experiment. The colony is decreasing by 15% per minute. Which function can be used to model the number of bacteria in the colony after x minutes?

f(x) = 12000(1.15)x

f(x) = 12000(0.15)x

f(x) = 12000(0.85)x

f(x) = 12000(1.85)x

Tags

CCSS.HSF.LE.A.2

5.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

The bear population in a given area is currently 1580. They anticipate the bear population to decrease by 2% each year. Which function represents the population of bears, B, after t years.

B = 1580(0.02)t

B = 1580(1 – 0.02)t

B = 1580(1 + 0.02)t

B = 1580(1 – 0.2)t

Tags

CCSS.HSF.LE.A.2

6.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

The value of a car is $15,000 and depreciates at a rate of 8% per year. What is the exponential equation?

y=8(15,000)x

y=15,000(0.92)x

y=15,000(1.08)x

y=15,000(0.08)x

Tags

CCSS.HSF.LE.A.2

7.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Media Image

What function is present? 

Absolute Value

Exponential Decay

Linear Equation

Exponential Growth

Tags

CCSS.HSF-IF.C.7E

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