The Distributive Property Model and Solve

Fill in the blank, what is the missing number?
5(235) = (5x200) + (5x____) + (5x5) 

• 5

• 35

• 7

• 30

Tags

CCSS.4.NBT.B.5

Which of the following shows the distributive property?

• 3 x 124 = (3x100) + (2x20) + (3x4)

• 3 x 124 = (3+100) x (3x24)

• 3 x 124 = 3 x 124

• 3 x 124 = 3(120+4) 

Tags

CCSS.3.OA.B.5

Fill in the blanks: 
6 x 268  = ( ___ x 200) + (6 x ____) + (6 x ____)

• 200,60,8

• 2,60,8

• 6,260,8

• 6,60,8

Tags

CCSS.4.NBT.B.5

Multiply 1,977 x 8
Use the Distributive Property to solve.

• 15,816

• 16,815

• 15,063

• 12,259

Tags

CCSS.5.NBT.B.5

Fill in the blanks: 
8x749 = (8 x _____) + (8 x _____) + (8 x ____) 

• 700, 49, 9

• 700,40,9

• 740,40,9

• 700,40,90

Tags

CCSS.4.NBT.B.5

Jaxon built the array to explain his thinking for 7 x 5. Which explanation matches his thinking?

• 7 x 3 = 21

  and 7 x 2 = 14

  14 + 21 = 35

• I am not good at knowing how to solve this kind of problem

• since 5 x 5 = 20

  and 3 x 5 = 15

  20 + 15 = 35

• I know 4 x 5 = 20 and 3 x 5 = 15

  20 + 15 = 35

Tags

CCSS.3.OA.C.7

The model makes difficult multiplication easier to solve. The original equation was:

• 8 x 8 = ?

• 5 x 8 = 40

• 7 x 8 = ?

• 7 x 16 = ?

Tags

CCSS.4.NBT.B.5

Braxton made this model for the problem 9 x 4. Finish his work, what would he do next and what would the product be?

• 9 x 4 = 36,

  36 + 18 = 54

  so, 9 x 4 = 54

• 9 x 2 = 18,

  18 + 18 = 36

  so, 9 x 4 = 36

• Braxton is finished, 9 x 4 = 18

Tags

CCSS.3.OA.A.1

Oscar was thinking about using a doubles strategy because 4 is an even number. Which equation could he use with this model?

• 4 x 6 = (2 x 5) + (2 x 1)

• 4 x 6 = (2 x 6) + (2 x 6)

• 4 x 6 = (1 x 6) + (3 x 6)

Tags

CCSS.3.OA.C.7

This array shows 4 rows of 8 strawberries. Draw a line to separate each array into two smaller arrays. Choose other possible answers, then write other new facts on a whiteboard and show them to a teacher.

• (5 x 9) + (0 x 9)

  (1 x 8) + (3 x 8)

• (4 x 4) + (4 x 4)

  (4 x 5) + (4 x 3)

  (2 x 8) + (2 x 8)

• 5 x 8 = 8 x 5

• (4 x 4) + (4 x 4)

  (5 x 8) + (3 x 8)

  4 x 8 = 32

Tags

CCSS.2.OA.C.4