Area, Perimeter, Circumference Word Problems

Area, Perimeter, Circumference Word Problems

7th Grade

14 Qs

quiz-placeholder

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Area, Perimeter, Circumference Word Problems

Area, Perimeter, Circumference Word Problems

Assessment

Quiz

Mathematics

7th Grade

Practice Problem

Hard

CCSS
7.G.B.4, 4.MD.A.3, 6.G.A.1

+1

Standards-aligned

Created by

Anthony Clark

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14 questions

Show all answers

1.

OPEN ENDED QUESTION

1 min • 2 pts

Media Image

In Hobbiton, hobbit houses have circular windows. A hobbit needs to replace a window which has a circumference of 4.8 metres. What is the area of the window?

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Answer explanation

We need to find the radius first using the circumference formula: 

C = 2πr

4.8 = 2πr

4.8 = 2 × 3.14 × r

 r = 4.8 ÷ (2 × 3.14) 

 r = 0.764 metres

Calculate the area

A = πr²

A  = 3.14 × (0.764)²

       = 3.14 × 0.584 

Tags

CCSS.7.G.B.4

2.

OPEN ENDED QUESTION

1 min • 2 pts

Media Image

The school is painting a mural on a wall shaped like a trapezium. The parallel sides of the wall are 8 metres and 12 metres long, and the height between them is 5 metres. How much paint will they need if 1L covers 10 square metres?

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Answer explanation

Area of trapezium

= ½(a+b)h

= ½(8+12) × 5

= 50m²

Paint needed

= 50 ÷ 10

Tags

CCSS.6.G.A.1

3.

OPEN ENDED QUESTION

1 min • 3 pts

Media Image

Hemi is creating a Maori-inspired artwork on a circular canvas. The outer edge of the canvas has a circumference of 188.4cm. He leaves a 5cm border around the edge unpainted. What is the area of the painted region?

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Answer explanation

Radius of canvas

= Circumference ÷ (2π) = 188.4 ÷ (2π) = 30 cm

Area of canvas

= πr² = π × 30² ≈ 2827.43 cm²

Radius of painted area

= 30 - 5 = 25 cm

Area of painted region

= π × 25² ≈ 1963.5 cm²

Tags

CCSS.7.G.B.4

4.

OPEN ENDED QUESTION

1 min • 3 pts

Media Image

A church is commissioning a circular stained glass window with a smaller circular design in its centre. The outer circle has a radius of 2.4 metres, while the inner circle has an area that is 1/9 of the total window area. What is the radius of the inner circle?

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Answer explanation

Area of outer circle

= πr² = π(2.4)² = 18.1 m² (rounded to one dp)

Area of inner circle

=The inner circle's area is 1/9 of the total area

   =  18.1 ÷ 9 = 2.01 m²

use the area formula for a circle to find the radius of the inner circle:

   2.01 = πr²

   r² = 2.01 ÷ π

   r = √(2.01 ÷ π) ≈ 0.8 m

5.

OPEN ENDED QUESTION

1 min • 4 pts

Media Image

A farmer notices a mysterious crop circle in his field. It's composed of two circles: a larger outer circle and a smaller inner circle. The area between the two circles is 200 square metres. If the radius of the larger circle is 10 metres, what is the radius of the smaller circle?

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Answer explanation

 Area between circles

= π(R² - r²) = 200

=  π(10² - r²) = 200

= 100π - πr² = 200

=  πr² = 100π - 200

= r² = 100 - 200/π ≈ 36.34

6.

OPEN ENDED QUESTION

1 min • 3 pts

Media Image

A school is renovating a classroom with an unusual shape. The room consists of a rectangle measuring 85m by 62m, with a semicircle attached to one of the longer sides. What is the total area of the floor that needs to be covered with new tiles?

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Answer explanation

Area of rectangle

= 85 m × 62 m = 527 m²

Calculate the area of the semicircle:

 The diameter of the semicircle is equal to the length of the rectangle 

   - Radius of semicircle = 85 m ÷ 2 = 42.5 m

   - Area of full circle = πr² = π(42.5)² ≈ 567 m²

   - Area of semicircle = 567 m² ÷ 2 ≈ 284 m²

Total area = Area of rectangle + Area of semicircle

         = 527 m² + 284 m² 

7.

OPEN ENDED QUESTION

1 min • 4 pts

Media Image

A new skateboard park is being designed in the shape of a trapezium. The parallel sides are 58m and 45m long, and the non-parallel sides are both 50m long. Inside the park, a circular area with a radius of 18 metres will be set aside for beginners. What percentage of the total park area is the beginners' circle?

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Answer explanation

  Area of trapezium = 2575m²

  Area of circle = πr² = π × 16² =  804.2477 = 804.25m²

  Percentage = (804.25 ÷ 2575) × 100 = 31.233%

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