Circumference and Volume

Circumference and Volume

7th Grade

9 Qs

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Circumference and Volume

Circumference and Volume

Assessment

Quiz

Mathematics

7th Grade

Hard

CCSS
8.G.C.9, 7.G.B.6, 7.G.B.4

+2

Standards-aligned

Created by

Anthony Clark

FREE Resource

9 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Media Image

Find the volume of the figure. Round to the nearest tenth.

80 cm³

40 cm²

80 cm2

40 cm³

Tags

CCSS.7.G.B.6

2.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Media Image

Find the volume of the figure. Round to the nearest tenth.

128.6 units³

1,286.8 units³

401.9 units³

5,144.6 units³

Tags

CCSS.8.G.C.9

CCSS.HSG.GMD.A.3

3.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Media Image

Cylinder A is similar to cylinder B. Find the volume of cylinder B.

168π in3

378π in3

126 in3

378 in3

4.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Media Image

Find the volume of the cone.

14.13 in3

56.55 in3

169.56 in3

18 in3

Tags

CCSS.8.G.C.9

CCSS.HSG.GMD.A.3

5.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Media Image

Find the volume of the sphere.

150.72 mm3

904.32 mm3

2,712.96 mm3

904.32 mm2

Tags

CCSS.8.G.C.9

CCSS.HSG.GMD.A.3

6.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Media Image

Identify and describe the solid produced by rotating the figure around the given axis.

cone with radius 5

cone with radius 9

cylinder with radius 5

cylinder with radius 9

Tags

CCSS.7.G.A.3

7.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

When the circumference is 125.6, what is the diameter?

C = πd

125.6 = 3.14d

C = π (r) (r)

125.6 = 3.14 (r)(r)

C = 2 π r

125.6 = 6.28r

C = 1/2 bh

125.6 = 1/2 (bh)

Tags

CCSS.7.G.B.4

8.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Media Image

The volume of this box is 240 cubic inches. V = Bh. The Base measurements are 10 x 12. What is the height?

h = 3 inches

h = 4 inches

h = 2 inches

h = 1.5 inches

Tags

CCSS.7.G.B.6

9.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

The circumference of a circle is 69.08. Find the radius.

C = π (r) (r)

69.08 = 3.14 (r) (r)

C = 2 π r

69.08 = 2 (3.14) r

C = 2 π d

69.08 = 2 (3.14) d

C = 2 π r

3.14 = 2 (69.08) r

Tags

CCSS.7.G.B.4