Substitution by System of Equations

What is the first step in solving a system by Substitution?

• Make sure both equations are in standard form.

• Make sure at least one equation is solved for one variable.

• Make sure both equations are in slope-intercept form.

• Make sure both equations can be solved.

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

Solve the system of equations by the substitution method

• (-6, 30)

• (-2, 10)

• (44, 39)

• No solution

• Infinite solutions

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

Solve the system of equations by substitution y = 4x+1 3x + 2y = 13

• (1, 5)

• (5, 1)

• (0.25, 2)

• (2, 0.25)

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

Solve the system of equations by substitution

y=2x

x + y = 9

• (6, 3)

• (3, 6)

• (-3, -6)

• no solution

Tags

CCSS.HSA.REI.C.7

Solve for x and y
2x − 3y = −1
 y = x − 1

• (-2,-3)

• (0,-1)

• (3,4)

• (4,3)

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

Solve the system:

y=4x-1

y=x/2+6

• (7, 2)

• (1, 3)

• (2, 7)

• (-2, 5)

• (8, 10)

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

• F

• G

• H

• J

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

Solve for x and y
y = 2x + 1
y = 4x - 1

• (1,3)

• (-1,-3)

• (-1,3)

• (3,1)

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

What is the solution to this system?

x - y = 6

y = 2x - 5

• (1, 3)

• (-1, 3)

• (-1, -7)

• (1, -7)

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

A system of equations is shown below.
3y = 2x + 4
x = 2y − 5
What is the solution to the system of equations? 

• (-1, -2)

• (2,1)

• (-2,1)

• (-1.2)

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6