Area and Equations

Which equation can be used to find A, the area of the parallelogram shown?

• A=½ (1.8)(2.5)

• A=(1.8)(2)

• A=½ (2)(2.5)

• A=(1.8)(2.5)

Tags

CCSS.6.G.A.1

Which equation could be used to find the area of the rectangle shown?

• A=½ (3.2)(7.5)

• A= (3.2)(7.5)

• A=(3.2)(7.5)÷2

• A=3.2+7.5

Tags

CCSS.3.MD.C.7B

CCSS.4.MD.A.3

A rectangular board has an area of A square inches. The width of the board is 12 inches. Which equation represents x, the length of the board in inches?

• x=A÷12

• x= 12 + A

• x=12÷A

• x =A- 2(12)

Tags

CCSS.6.EE.B.7

Which equation could be used to find A, the area of the triangle shown?

• ½(16+11)9.4

• ½(16)(9.4)

• (16)(9.4)

• ½(11)(9.4)

Tags

CCSS.6.G.A.1

The table shows the relationship between perimeter and area of four different squares. Which equation could be used to find A, the area of a square that has a perimeter of P units?

• A= (P÷4) x (P÷4)

• A=P- 4

• A= (P+4) x (P+4)

• A= P

Tags

CCSS.3.MD.C.7B

CCSS.4.MD.A.3

A triangular shaped candy has an area of A square inches. The base of the candy is 5 inches. Which equation represents x, the height of the candy in inches?

• x= 5÷A

• x= A-2.5

• x=½A+6

• x=A÷2.5

Tags

CCSS.6.EE.B.7

Which equation could be used to find the area of the trapezoid shown?

• A= ½(7+4)2.8

• A=½(7+4)2

• A=½(7+4)2.2

• A=½(4)(2)

Which equation could be used to find A, the area of the triangle shown.

• A=(11)(5.1)

• A=½ (11+8)5.1

• A= ½(11)(5.1)

• A=½(11)(8)+5.1

Tags

CCSS.6.G.A.1

The face of a lamp shade is shaped like a trapezoid. The dimensions of the face are shown in the diagram. Which equation could be used to find A, the area of the face of the lamp shade in square inches?

• A=½(6+10)y

• A=½(6+10)x

• A=½(6)+(10)x

• A=½(6)+(9)y

Tags

CCSS.6.G.A.1

Maggie wants to find the area of the parallelogram shown. Which method could she use to correctly find the area of the parallelogram?

• A=½(10)(6)

• A=(10)(6)

• A=(10)(7)

• A=½(10+6)7

Tags

CCSS.6.G.A.1