
Quadratics Story Problem
Authored by Barbara White
Mathematics
9th Grade

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9 questions
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1.
MULTIPLE CHOICE QUESTION
5 mins • 1 pt
An object in launched directly upward at 64 feet per second (ft/s) from a platform 80 feet high. Its height is represented by the equation s(t) = –16t2 + 64t + 80. What will be the object's maximum height?
2 ft
80 ft
144 ft
5 ft
2.
MULTIPLE CHOICE QUESTION
5 mins • 1 pt
An object in launched directly upward at 64 feet per second (ft/s) from a platform 80 feet high. Its height is represented by the equation s(t) = –16t2 + 64t + 80. What time will be the object reach it's maximum height?
2 s
80 s
144 s
5 s
3.
MULTIPLE CHOICE QUESTION
5 mins • 1 pt
An object in launched directly upward at 64 feet per second (ft/s) from a platform 80 feet high. Its height is represented by the equation s(t) = –16t2 + 64t + 80. What time will the object reach the ground?
2 s
80 s
144 s
5 s
4.
MULTIPLE SELECT QUESTION
5 mins • 1 pt
The quadratic equation f(x) = -16t2 + 64t models the height of a golf ball in feet over time in seconds. How long was the ball moving through the air?
10 seconds
8 seconds
6 seconds
4 seconds
5.
MULTIPLE SELECT QUESTION
5 mins • 1 pt
The quadratic equation f(x) = -16t2 + 64t models the height of a golf ball in feet over time in seconds. What is the height of the ball after exactly 1 second?
28 ft
48 ft
60 ft
64 ft
6.
MULTIPLE SELECT QUESTION
3 mins • 1 pt
The quadratic equation f(x) = -16t2 + 64t models the height of a golf ball in feet over time in seconds. At what time is the ball exactly 64 feet above the ground?
6 seconds
4 seconds
2 seconds
1 second
7.
MULTIPLE CHOICE QUESTION
5 mins • 1 pt
A diver is standing on a platform above the pool. He jumps form the platform with an initial upward velocity of 8 ft/s. Use the formula
h(t) = −16t2 + 8t + 24, where h is his height above the water, t is the time, v is his starting upward velocity, and s is his starting height. How high is the platform?
.25 ft
24 ft
25 ft
8 ft
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