Solutions to Quadratic Systems

Solve the System Graphically.
y=-(x-2)²+4
y=-5

• (-1,-5)
• (5,-5)
• (-1,-5) and (5,-5)
• (-5,5) 

Tags

CCSS.HSA.REI.C.7

Solve the system graphically.
y-3=(x-1)²
2x+y=5

• (-1,7) and (1,3)
• (7,-1) and (3,1)
• (1,-7) and (-1,3)
• (-1,7) and (1,-3) 

Tags

CCSS.HSA.REI.C.7

Solve the system graphically.
5-y=x²+x
y+1=3/4x

• close to (3,4) and (-2,0)
• close to (-3,4) and (2,0)
• close to (3,-4) and (0,2)
• close to (-3,-4) and (2,0)

Tags

CCSS.HSA.REI.C.7

Solve the system algebraically.
6x+y=-16
y+7=x²

• (-3,2) and (0,0)
• (3,-2)
• (-3,2)
• (3,-2) and (0,0)

Tags

CCSS.HSA.REI.C.7

Solve the system algebraically.
y-5=(x-2)²
x+2y=6

• (0,0)
• No Solution
• (0,2)
• (2,0)

Tags

CCSS.HSA.REI.C.7

Solve the system algebraically.
y²-26=-x²
x-y=6

• (-1,-5) and (-5,-1)
• (-1,5) and (-5,1)
• (1,-5) and (5,-1)
• (1,-5)

Tags

CCSS.HSA.REI.C.7

Jason is driving his car on a highway at a constant rate of 60 miles per hour when he passes his friend Alan whose car is parked on the side of the road. Alan has been waiting for Jason to pass so that he can follow him to a nearby campground. To catch up to Jason's passing car, Alan accelerates at a constant rate. The distance d, in miles,that Alan's car travels as a function of time t, in hours, since Jason's car has passed is given by d = 3600t². How long does it takes Alan's car to catch up with Jason's car?

• 1/60 of an hour
• 1 minute
• 1/6 of an hour
• 10 minutes

Amy throws a quarter from the top of a building at the same time that a balloon is released from the ground. The equation describing the height y above ground of the quarter in feet is y = 64 - 2x² , where x is the time in seconds. The equation describing the elevation of the balloon in feet is y = 6x + 8, where x is the time in seconds. After how many seconds will the balloon and quarter pass each other?Check your solution for reasonableness.

• x=-7 and x=4
• 7 seconds
• 4 seconds
• 4 and 7 seconds