Algebra II I'm Working Backwards Complex Numbers

Simplify:

3 - 4i - (6i - 2)

• 5 - 10i

• 1 - 10i

• 1 - 2i

• 5 - 2i

Tags

CCSS.HSN.CN.A.2

Simplify:

4 - 5i + 7 + 10i

• -3 + 15i

• 16i

• 11 + 15i

• 11 + 5i

Tags

CCSS.HSN.CN.A.2

Simplify:

-2(6 - 2i)

• -12 - 4i

• 12 - 4i

• -12 + 4i

• 12 + 4i

Tags

CCSS.HSN.CN.A.2

Simplify:

(2 + 3i)(2 - 3i)

• 4 + 9i

• 13

• -5

• -5i

Tags

CCSS.HSN.CN.C.8

Simplify:

(2 - 5i)(4 + i)

• 13

• 3

• 6 - 4i

• 13 - 18i

Tags

CCSS.HSN.CN.A.2

Simplify:

(-2 + i)²

• 3

• 4 + i²

• 3 - 4i

• 4i²

Tags

CCSS.HSN.CN.C.8

What does i² = ?

• -1
• √-1
• 1
• -√1

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CCSS.HSN.CN.A.1

Find the sum.
(5-2i) + (-7+8i)

• -2+6i
• 12+6i
• -35-16i²
• -35 -16i

Tags

CCSS.HSN.CN.A.2

The product of (3 -2i) and (7+6i) is

• 21 - 12i
• 9 + 4i
• 33 + 4i
• 21 + 16i

What is the value of the expression below?

(2 + 4i) + i(2 + i)

• 4 + 5i

• 2 + 7i

• 7i

• 1 + 6i

Tags

CCSS.HSN.CN.A.2