Finding Center and Radius of Circles Written in Standard Form

What is the coordinates of the centre and the radius of the circle with equation:
(x - 4)^2 + (y - 3)^2 = 25^ ?

• Centre  (4,3)
  Radius = 5 units
• Centre  (4,3)
  Radius = 25 units
• Centre  (-4,-3)
  Radius = 25 units
• Centre  (-4,-3)
  Radius = 5 units

Tags

CCSS.HSG.GPE.A.1

What is the equation of the circle, with centre (4,2) and radius 5 units?

• (x + 4)^2 + (y + 2)^2 = 25
• (x + 4)^2 + (y + 2)^2 = 5
• (x - 4)^2 + (y - 2)^2 = 5
• (x - 4)^2 + (y - 2)^2 = 25

Tags

CCSS.HSG.GPE.A.1

What is the coordinates of the centre and the radius of the circle with equation:
(x + 3)^2 + (y + 1)^2 = 2^2 ?

• Centre  (-3,-1)
  Radius = 4 units
• Centre  (3,1)
  Radius = 2 units
• Centre  (-3,-1)
  Radius = 2 units
• Centre  (3,1)
  Radius = 4 units

Tags

CCSS.HSG.GPE.A.1

The diameter of a circle has length 12. The center is at (-5, 2). Give the equation of the circle.

• (x - 2)² + (y + 5)² = 36
• (x - 5)² + (y + 2)² = 6
• (x + 5)² + (y - 2)² = 36
• (x + 2)² + (y - 5)² = 6

Tags

CCSS.HSG.GPE.A.1

Which graph corresponds to 
(x)²+ (y-6)²=9

• A
• B
• C
• D

Tags

CCSS.HSG.GPE.A.1

What is the correct equation of the given circle in general form?

• A

• B

• C

• D

Tags

CCSS.HSG.GPE.A.1

Determine the equation of the circle in standard form:
x² + y² + 4x + 6y - 36 = 0

• (x+2)² + (y+3)² = 49
• (x+2)² + (y+3)² = 13
• (x-2)² + (y-3)² = 49
• (x-2)² + (y-3)² = 13

Tags

CCSS.HSG.GPE.A.1

Determine the equation of the circle in standard form: x² + y² + 6x - 12y + 20 = 0

• (x-3)² + (y+6)² = 25
• (x+3)² + (y-6)² = 25
• (x-3)² + (y+6)² = 45
• (x+3)² + (y-6)² = 5

Tags

CCSS.HSG.GPE.A.1

Determine the center and radius:
x² + y² - 10x + 8y -8 = 0

• C = (5,-4) r = 7
• C = (-5,4) r = 7
• C = (-4,5) r = 49
• C = (5,-4) r = 49

Tags

CCSS.HSG.GPE.A.1

Determine the equation of the circle in standard form: x² + y² + 6x - 12y + 20 = 0

• (x-3)² + (y+6)² = 25
• (x+3)² + (y-6)² = 25
• (x-3)² + (y+6)² = 45
• (x+3)² + (y-6)² = 5

Tags

CCSS.HSG.GPE.A.1