Profit Curve Practice 24-25

The profit from selling local ballet tickets depends on the ticket price. Using past receipts, we find that the profit can be modeled by the function:

p= -15x² +600x +60

What is the maximum profit you can make from selling tickets?

• $6060

• $20

• $600

• $10,250

The profit from selling local ballet tickets depends on the ticket price. Using past receipts, we find that the profit can be modeled by the function:

p= -15x² +600x +60

How much would the ticket cost in order to make no profit?

• $6060

• $20

• $40.10

The profit from selling local ballet tickets depends on the ticket price. Using past receipts, we find that the profit can be modeled by the function:

p= -15x² +600x +60

What would the ticket price be to make a maximum profit?

• $6060

• $20

• $600

• $40.10

The graph shows how price affects profit. If a company is operating at (50, 8000) , what should they do to improve their profits? 

• Lower Price 
• Raise Price 

The graph shows how price affects profit. What is the maximum profit?

• $12,500

• $35

• $10

• $60

The graph shows how price affects profit. What selling price will give the company's maximum profit?

• $12,500

• $35

• $10

• $60

The graph shows how price affects profit. What selling price will cause the company to make no money?

• $12,500

• $35

• $10

• $60

The graph shows how price affects profit. If the company is currently operating at the point (20, 6000), what should the company do differently to reach the maximum profit? 

• Lower Price 
• Raise Price 

The graph shows how price affects profit. What is a reasonable domain for this graph?

• (10,60)

• (-∞, ∞)

• (0,12500)

• (-2000, 12500)

The graph of the quadratic function represents the profit for Jose's Soccer Ball Company.

According to the graph, how much should Jose charge for each soccer ball in order to have a maximum profit?

• $2.00

• $8.50

• $14.50

• $240.00