Algebra 1 Final Review

Algebra 1 Final Review

8th Grade

40 Qs

quiz-placeholder

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Algebra 1 Final Review

Algebra 1 Final Review

Assessment

Quiz

Mathematics

8th Grade

Practice Problem

Hard

CCSS
HSA.REI.D.12, 7.EE.B.4A, HSA.CED.A.4

+11

Standards-aligned

Created by

Brent Ha

Used 4+ times

FREE Resource

40 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

Brenda's gym charged $10 fee to join plus $29 per month. She calculated that the gym has cost her a total of $155 since she joined. Which equation could be used to determine the number of months(m) Brenda has been going to the gym?

10m + 29 = 155

10 + 29 = 155m

10 + 29m = 155

m + 29 = 155 - 10

2.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

Ellie bought cookies and cupcakes from Giant for $102.44. If she spent $36.44 on cookies and the cupcakes are $11 per box, which equation represents how many boxes of cookies she bought?

102.44 + 36.44x = 11

102.44x + 11 = 36.44

11x + 36.44 = 102.44

11x+ 36.44 =102.44\frac{11}{x}+\ 36.44\ =102.44

Tags

CCSS.HSA.CED.A.3

3.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

 A computer printer can print 10 pages per minute. There were already 35 pages in the tray.  The total pages printed was 115 pages. How many minutes has the printer been running?
8
9
7
10

Tags

CCSS.7.EE.B.4A

4.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Pizzazz Publications is having some books printed. The printer charges $800 plus $5 per book. What equation could help me find how many books can be printed for $4,000?
800 + 5x = 4000
800x + 5 = 4000
4000 + 5x= 800
800 + 5 = 4000

Tags

CCSS.HSA.CED.A.3

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Tags

CCSS.HSA.CED.A.4

6.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

Media Image

Solve the formula for y. What is the 1st step?

Subtract B from each side.

Divide each side by Ax.

Divide each side by B.

Subtract Ax from each side.

Tags

CCSS.HSA.CED.A.4

7.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

  u = bak \ u\ =\ bak\      Solve for  a

 a=ubka=\frac{u}{bk}  

 a = bkua\ =\ \frac{bk}{u}  

 a = bkua\ =\ -\frac{bk}{u}  

 a=ubka=-\frac{u}{bk}  

Tags

CCSS.HSA.CED.A.4

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