Solving Radical Equations

Solving Radical Equations

Assessment

Flashcard

Mathematics

10th - 12th Grade

Hard

CCSS
HSA.REI.A.2, HSA-REI.B.4B

Standards-aligned

Created by

Wayground Content

FREE Resource

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15 questions

Show all answers

1.

FLASHCARD QUESTION

Front

What is a radical equation?

Back

A radical equation is an equation in which a variable is contained within a radical (square root, cube root, etc.).

Tags

CCSS.HSA.REI.A.2

2.

FLASHCARD QUESTION

Front

How do you isolate a variable in a radical equation?

Back

To isolate a variable in a radical equation, you can square both sides of the equation to eliminate the radical, then solve for the variable.

Tags

CCSS.HSA.REI.A.2

3.

FLASHCARD QUESTION

Front

What is the first step in solving the equation √(x + 5) = 8?

Back

The first step is to square both sides of the equation to eliminate the square root, resulting in x + 5 = 64.

Tags

CCSS.HSA.REI.A.2

4.

FLASHCARD QUESTION

Front

What are extraneous solutions in radical equations?

Back

Extraneous solutions are solutions that emerge from the process of solving the equation but do not satisfy the original equation.

Tags

CCSS.HSA.REI.A.2

5.

FLASHCARD QUESTION

Front

How can you check if a solution is extraneous?

Back

To check if a solution is extraneous, substitute it back into the original equation to see if it holds true.

Tags

CCSS.HSA.REI.A.2

6.

FLASHCARD QUESTION

Front

What is the principle of squaring both sides of an equation?

Back

The principle states that if two expressions are equal, squaring both sides will maintain the equality, but it may introduce extraneous solutions.

Tags

CCSS.HSA.REI.A.2

7.

FLASHCARD QUESTION

Front

What is the solution to the equation √(x) = 5?

Back

The solution is x = 25, obtained by squaring both sides of the equation.

Tags

CCSS.HSA.REI.A.2

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