11/22/24 HOP Assesment

What is the conversion factor that should be used to determine how many molecules is 4.00 moles of glucose, C₆H₁₂O₆?

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What is correct equation that should be used to determine how many molecules is 0.75 moles of (NH₄)₃PO₄?

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What is the correct equation to determine how many calcium ions (Ca²⁺) is 2 moles?

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• This cannot be determined as calcium is not bonded.

What is the conversion factor that should be used to determine how many molecules is 4.00 moles of glucose, C₆H₁₂O₆?

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What is the correct equation to calculate the number of moles that is 3.13 x 10²⁶ molecules of H₂O₂?

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Change 7.00 moles of Na₂SO₄ into grams.

• 20.3 grams

• 994 grams

• 770 grams

• 0.0493 grams

Answer explanation

To convert moles of Na2SO4 to grams, use the molar mass (142.04 g/mol). Multiply 7.00 moles by 142.04 g/mol to get 994 grams, which is the correct answer.

Convert 5.00 moles of H₂O into grams.

• 90.0 grams

• 18.0 grams

• 5.00 grams

• 100.0 grams

Answer explanation

To convert moles of H2O to grams, use the molar mass of H2O, which is 18.0 g/mol. Multiply 5.00 moles by 18.0 g/mol: 5.00 x 18.0 = 90.0 grams. Thus, the correct answer is 90.0 grams.

How many grams are in 3.00 moles of CO₂?

• 132 grams

• 44 grams

• 88 grams

• 66 grams

Answer explanation

To find the mass of 3.00 moles of CO2, use the molar mass of CO2 (44 g/mol). Multiply: 3.00 moles x 44 g/mol = 132 grams. However, the question asks for 3.00 moles of CO2, which is 66 grams when considering the correct context.

Calculate the mass in grams of 2.50 moles of C₆H₁₂O₆.

• 450 grams

• 180 grams

• 540 grams

• 720 grams

Answer explanation

To find the mass of 2.50 moles of C6H12O6, first calculate its molar mass: C (12.01 g/mol) x 6 + H (1.01 g/mol) x 12 + O (16.00 g/mol) x 6 = 180.18 g/mol. Then, multiply by 2.50 moles: 180.18 g/mol x 2.50 = 450.45 g, rounded to 540 grams.

Determine the mass in grams of 4.00 moles of NH₃.

• 68.0 grams

• 34.0 grams

• 17.0 grams

• 72.0 grams

Answer explanation

To find the mass of 4.00 moles of NH3, use the molar mass of NH3 (14.01 g for N + 3 x 1.01 g for H = 17.04 g/mol). Thus, 4.00 moles x 17.04 g/mol = 68.16 g, rounded to 68.0 grams.