Unit 2 Advisory Assignment - Math

3+(-5)

• 8

• 2

• -2

• -8

Answer explanation

- Adding integers

- Signs are different

- Subtract numbers (5-3=2)

- Bigger number is negative, so answer is negative

- 3-5=-2

Tags

CCSS.7.NS.A.1C

-6-9

• 3

• -15

• -3

• 15

Answer explanation

- Subtracting integers

- Signs are treated as the same

- Add numbers (6+9=15)

- both numbers are treated as negative, so answer is negative

- -6-9=-15

Tags

CCSS.7.NS.A.1C

-4x7

• 14

• -28

• 3

• 28

Answer explanation

- Multiplying integers

- 4x7=28

- signs are different, so answer is negative

- -4x7=-28

Tags

CCSS.7.NS.A.2A

CCSS.7.NS.A.2B

25/5

• 125

• -5

• 5

• 1

Answer explanation

- Dividing integers

- signs are same, so answer is positive

- 25/5=5

-4+(-8)

• 4

• -12

• 12

• -4

Answer explanation

- Adding integers

- Signs are same

- Add numbers (4+8=12)

- Both numbers are negative, so answer is negative

- -4+(-8)=-12

Tags

TEKS.MATH.6.3D

6-(-8)

• 14

• 2

• -2

• 5

Answer explanation

- Subtracting integers

- minus a negative is same thing as a positive

- 6-(-8) is same as 6+8

- 6+8=14

Tags

CCSS.7.NS.A.1C

-8x(-6)

• -14

• -48

• 2

• 48

Answer explanation

- Multiplying integers

- 8x6=48

- signs are the same, so answer is positive

- -8x(-6)=48

Tags

CCSS.7.NS.A.2A

CCSS.7.NS.A.2B

-60/6

• -54

• 30

• 10

• -10

Answer explanation

- Dividing integers

- 60/6=10

- signs are different, so answer is negative

- -60/6=-10

Tags

CCSS.7.NS.A.2A

CCSS.7.NS.A.2B

Use a proportion (WKU) to find the missing side, x.

• 5

• 180

• 8

• 30

Tags

CCSS.7.RP.A.3

Use a proportion (WKU) to find the missing side length, MN.

• 10

• 6

• 8

• 5

Tags

CCSS.7.RP.A.2B