Pseudocode Quiz

Consider the pseudocode procedure findMaxDigit, which is intended to return the maximum digit in the integer num. For example, if num is 294, findMaxDigit returns 9 because 9 is the maximum digit in 294. // precondition: num is a positive integer greater than 0 int findMaxDigit (int num) int maxDigit ← /* missing code segment */ while (num > 0) int digit ← num % 10 if ( digit > maxDigit ) maxDigit ← digit end if num ← num / 10 //Division symbol uses integer division end while return maxDigit end findMaxDigit Which of the following could replace /* missing code segment */ so that findMaxDigit works as intended?

• num / 10 + 10

• num % 10

• num * 10

• num + 10

Consider the following function: void drawTriangle () // print a line break after each print statement print "*" print "**" print "***" print "****" end drawTriangle What would happen as a result of calling drawTriangle()?

• **********

• * ** *** ****

• *

• ****

• **

Consider the following pseudocode procedure. // precondition: k is a positive integer greater than 1 void mystery(int k) for (int c = 1; c < k; c = c + 1) print c + " " end for end mystery Which of the following best describes procedure mystery?

• It returns all the values from 1 to k.

• It returns all the values from 1 to k-1.

• It prints all the values from 1 to k.

• It prints all the values from 1 to k - 1.

Consider the following procedure and procedure call: void practice( int Y) int X ← 10 Y ← Y + 5 if ( X > Y) print “Hello” else print “world” end if end practice practice(5) What would print as a result of executing the code?

• Nothing because the function is defined as VOID

• Hello

• Hello world

• world

Consider the following procedure header: int getSum(int num1, int num2, int num3) Which procedure call is valid?

• getSum("A", 96, 95)

• getSum(94.5, 96, 95)

• getSum(96, 95)

• getSum(getSum(92, 93, 95), 96, 95)

Consider the pseudocode procedure swapValues that is intended to swap the values of the two integer variables m and n. void swapValues( int m, int n) /* missing code segment */ end swapValues Which of the following could replace /* missing code segment */ so that swapValues works as intended?

• int temp ← m n ← m m ← n

• int temp ← m m ← n n ← temp

• int temp ← n m ← n n ← temp

• int temp ← n n ← m m ← n

Consider the following pseudocode procedure and procedure call: void practicePassing( pass-by-reference int X, pass-by-value int Y) Y = X / 2 // Division symbol uses integer division X = Y + 3 print X, Y end practicePassing Int i = 2 Int j = 3 practicePassing( i, j) print i, j What would print as a result of executing the code?

• 4 1 4 3

• 4 1 2 3

• 6 1 6 3

• 4 1 2 1

Consider the pseudocode procedure. void mystery () for ( int i = 0; i < 3; i = i + 1 ) for ( int j = 0; j < 4; j = j + 1 ) print “Hello” end for end for end mystery Which of the following best describes how changing the outer for loop to for ( int i = 0; i <= 2; i = i + 1 ) affects the output of the code segment?

• The output of the code segment will be unchanged.

• The string "Hello" will be printed more times because the outer loop will execute more times.

• The string "Hello" will be printed fewer times because the outer loop will execute fewer times.

• The string "Hello" will be printed fewer times because the inner loop will execute fewer times in each iteration of the outer loop.

Consider the following pseudocode procedure: void changeTemp( boolean airFlowing) int currentTemp = 68 if (airFlowing = = true) currentTemp = currentTemp + 2 else print “A/C is off” end if end changeTemp What happens for the method call changeTemp (true)

• “A/C is off” is printed

• An error prevents it from executing

• The variable currentTemp is increased to 70

• “A/C is off” is printed and the variable currentTemp is increased to 70

The pseudocode procedure drawCircle (xCor, yCor, r) is used to draw a circle on a coordinate grid. The center of the circle is at the coordinate (xCor, yCor) with a radius of r units. The procedure will be used to draw the following figure on a coordinate grid.

• xCor + 7 yCor + 2 for (int i = 1; i ≤ 3; i = i + 1) drawCircle(xCor, yCor, 2) xCor = xCor + 2 yCor = yCor - 2 end for

• xCor + 5 yCor + 4 for (int i = 1; i ≤ 3; i = i + 1) drawCircle(xCor, yCor, 2) xCor = xCor + 2 yCor = yCor + 2 end for

• xCor + 3 yCor + 6 for (int i = 1; i ≤ 4; i = i + 1) drawCircle(xCor, yCor, 2) xCor = xCor + 2 yCor = yCor + 2 end for

• xCor + 3 yCor + 6 for (int i = 1; i ≤ 3; i = i + 1) drawCircle(xCor, yCor, 2) xCor = xCor + 2 yCor = yCor - 2 end for