Understanding Redox Reactions Quiz

Quiz
•
Chemistry
•
University
•
Hard
+2
Standards-aligned
Badrinath Dhakal
Used 1+ times
FREE Resource
12 questions
Show all answers
1.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
+4
+6
-2
0
Answer explanation
In H2SO4, the total oxidation state of oxygen is -8 (4 O atoms at -2 each). Hydrogen contributes +2 (2 H atoms at +1 each). To balance, sulfur must have an oxidation number of +6, making the correct answer +6.
2.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
Which of the following reactions is a redox reaction?
Answer explanation
The reaction H2 + Cl2 → 2HCl is a redox reaction because hydrogen is oxidized (loses electrons) and chlorine is reduced (gains electrons), resulting in a change in oxidation states.
Tags
NGSS.HS-PS1-2
3.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
Answer explanation
In the reaction, Zn is oxidized as it loses two electrons to form Zn^{2+}. Cu^{2+} is reduced to Cu, while Zn^{2+} and Cu are the products. Therefore, the species that is oxidized is Zn.
Tags
NGSS.HS-PS1-1
NGSS.HS-PS1-2
4.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
Answer explanation
In acidic solution, MnO4^- is reduced to Mn^2+ and Fe^2+ is oxidized to Fe^3+. Balancing gives 5Fe^{2+} and 8H^+ to balance charges and atoms, resulting in MnO_4^- + 5Fe^{2+} + 8H^+ → Mn^{2+} + 5Fe^{3+} + 4H_2O.
5.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
Which of the following statements is true about an electrochemical cell?
Electrons flow from the cathode to the anode.
Oxidation occurs at the cathode.
Reduction occurs at the anode.
Electrons flow from the anode to the cathode.
Answer explanation
In an electrochemical cell, electrons flow from the anode (where oxidation occurs) to the cathode (where reduction occurs). Therefore, the correct statement is that electrons flow from the anode to the cathode.
Tags
NGSS.HS-PS3-5
6.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
+1.10 V
-1.10 V
+0.42 V
-0.42 V
Answer explanation
To find the standard cell potential, use the formula: E°cell = E°(cathode) - E°(anode). Here, Cu is reduced (cathode) and Zn is oxidized (anode). Thus, E°cell = 0.34 V - (-0.76 V) = +1.10 V.
7.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
Answer explanation
In the reaction, aluminum (Al) donates electrons to copper ions (Cu^{2+}), reducing them to copper (Cu). Therefore, Al is the reducing agent as it undergoes oxidation to Al^{3+}.
Tags
NGSS.HS-PS1-2
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