AP 2.7 VSPER and Hybridization

AP 2.7 VSPER and Hybridization

11th Grade

48 Qs

quiz-placeholder

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AP 2.7 VSPER and Hybridization

AP 2.7 VSPER and Hybridization

Assessment

Quiz

Chemistry

11th Grade

Hard

NGSS
HS-PS1-1, HS-PS1-4, HS-PS1-2

+1

Standards-aligned

Created by

Tod Elford

FREE Resource

48 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

According to the VSEPR model, the progressive decrease in the bond angles in the series of molecules CH₄, NH₃, and H₂O is best accounted for by the

increasing strength of the bonds

increasing electronegativity of the central atom

increasing number of unshared pairs of electrons

decreasing repulsion between hydrogen atoms

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Media Image

Which of the following complete Lewis diagrams represents a molecule containing a bond angle that is closest to 120°?

Option A diagram

Option B diagram

Option C diagram

Option D diagram

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Media Image

A Lewis diagram for the molecule C₂H₄ is shown above. In the actual C₂H₄ molecule, the H-C-H bond angles are closest to

90°

109.5°

120°

180°

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the approximate H—O—C bond angle in the glycinium cation?

180°

120°

105°

90°

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Which of the following is true about the geometry of the glycinium cation?

The leftmost C atom and all the atoms directly bonded to it lie in the same plane.

Both C atoms and both O atoms lie in the same plane.

The N—C—C bond angle is 180°.

The geometry around the N atom is planar.

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Media Image

When Reaction 3 occurs, does the hybridization of the carbon atoms change?

Yes; it changes from sp to sp².

Yes; it changes from sp to sp³.

Yes; it changes from sp² to sp³.

No; it does not change.

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Media Image

Lewis electron-dot diagrams for CO₂ and SO₂ are given above. The molecular geometry and polarity of the two substances are

the same because the molecular formulas are similar

the same because C and S have similar electronegativity values

different because the lone pair of electrons on the S atom make it the negative end of a dipole

different because S has a greater number of electron domains (regions of electron density) surrounding it than C has

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