MCQ 14_Millikan's Oil Drop Experiment Basics

MCQ 14_Millikan's Oil Drop Experiment Basics

12th Grade

8 Qs

quiz-placeholder

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MCQ 14_Millikan's Oil Drop Experiment Basics

MCQ 14_Millikan's Oil Drop Experiment Basics

Assessment

Quiz

Physics

12th Grade

Easy

Created by

reema chhetri

Used 2+ times

FREE Resource

8 questions

Show all answers

1.

MULTIPLE SELECT QUESTION

15 mins • 1 pt

Select all that apply. What was the main purpose of Millikan's oil drop experiment?

to determine the magnitude of the acceleration due to gravity

to determine the ideal voltage that batteries should contain

to determine the charge of an electron

to determine the mass of a proton

2.

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

Millikan determined that

the acceleration due to gravity is 9.8 m/s2

the charge of an electron is -1.60 * 1019 C

the universal gravitational constant is 6.67 * 10-11 m3/kgs2

everything is relative

3.

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

In Millikan's experiment, he examined these forces acting on oil drops:

gravity and normal

normal and friction

electric and normal

gravity and electric

4.

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

In order to equate the two forces, the oil drop had to be

stationary

moving upward

moving downward

moving diagonally

5.

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

The oil drop's movement was altered by

jedi mind powers

holding/poking the oil drop with a toothpick

changing gravity

changing the voltage across the charged plates

6.

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

If the charge on an oil drop was -2.72 * 10-18 C, how many electrons were absorbed by the oil drop?

2

5

13

17

7.

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

If an oil drop absorbed 4 electrons, what would its total charge be?

6.4 * 10-19 C

-6.4 * 10-19 C

8.9 * 10-18 C

-8.9 * 10-18 C

8.

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

When comparing the charges of electrons and protons, we can say that

their charges are equal in magnitude and sign

their charge magnitudes and signs are different

their charges are equal in magnitude but opposite in sign

their charge magnitudes are different but their signs are the same